Kmno4+so2+h2so4= mnso4+k2so4+h2o trim

Kmno4+so2+h2so4= mnso4+k2so4+h2o trim

Can't flatten.
H2so4 shall be product, h2o shall be reactant,
If exchanged, the factor is 25212

I can't.
H2so4 shall be product, h2o shall be reactant,
If exchanged, the factor is 25212

Does all benzene homologues fade acid potassium permanganate solutions? If there's something you ca n' t do, why?

Benzoic acid is always obtained when homologues of benzene, such as toluene or other alkyl benzene, react with potassium permanganate,
Can be depigmented, but the carbon atoms associated with the benzene ring do not contain hydrogen, such as tert-butylbenzene side chains are not easily
It is oxidized to carboxyl group and can not decolor potassium permanganate.

Benzoic acid is always obtained when homologues of benzene such as toluene or other alkyl benzene react with potassium permanganate,
Can be depigmented, but the carbon atoms associated with the benzene ring do not contain hydrogen, such as tert-butylbenzene side chains are not easily
It is oxidized to carboxyl group and can not decolor potassium permanganate.