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The absolute value of (a+b+2) is opposite to the fourth power of (2ab-1). Solve (a+b)(a+b)/3ab-3ab/(a+b)+1
The absolute value of (a+b+2) is greater than or equal to 0, and the fourth power of (2ab-1) is greater than or equal to 0. Since two opposite numbers can only be equal to 0, a+b+2=0,2ab-1=0 gives a+b=-2, ab=0.5, and the result is substituted.
Given a-b=1, the value of algebraic expression 2a-2b-3 is () A.-1 B.1 C.-5 D.5
A-b=1,
2A-2b-3=2(a-b)-3=2×1-3=-1.
Therefore, A.
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