Square of a ×4th power of a +5th power of a × a -3rd power of a ×3rd power of a

Square of a ×4th power of a +5th power of a × a -3rd power of a ×3rd power of a

Square of a ×4th power of a +5th power of a × a -3rd power of a ×3rd power of a
=6Th power of a +6th power of a -6th power of a
=6Th power of a
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Given the square of 1+a+a=0, find the value of the third power of 1+a+a+4th power of a+5th power of a+6th power of a+7th power of a+8th power of a

1+A+a^2+a^3+a^4+a^5+a^6+a^7+a^8
=(1+A+a^2)+(a^3+a^4+a^5)+(a^6+a^7+a^8)
=(1+A+a^2)+a^3(1+a+a^2)+a^6(1+a+a^2)
If 1+a+a^2=0, then the above formula =0