Given that a is the smallest positive integer, b and c are rational numbers, and |2+b||3a+2c|=0, find the value of the formula a+b+c

The absolute value is non-negative, and the sum of the two non-negative numbers is 0
So both numbers are 0.
2+B=0
3A+2c=0
Also known a=1
Resolved:
A =1
B=-2
C=-1.5
A+b+c=1-2-1.5=-2.5

The absolute value is non-negative, and the sum of the two non-negative numbers is 0
So both numbers are 0.
2+B=0
3A+2c=0
Also known a=1
Solution:
A =1
B=-2
C=-1.5
A+b+c=1-2-1.5=-2.5

The absolute value is non-negative, and the sum of the two non-negative numbers is 0
So both numbers are zero.
2+B=0
3A+2c=0
Also known a=1
Solution:
A =1
B=-2
C=-1.5
A+b+c=1-2-1.5=-2.5

A, b, c are positive integers, and (√3a+b)/(√3b+c) are rational numbers, find the value of (a+b+c)/(a+b+c).

(√3A+b)(√3b-c)/(3b^2-c^2)=[3ab-bc 3(-ac+b^2)]/(3b^2-c^2),(√3a+b)/(√3b+c) is a rational number, ac=b^2, a, b, c is an equal ratio sequence.(a+b+c)/(a+b+c)=a-b+c

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