What is the single digit of the 2003 power of 2 multiplied by the 2004 power of 3

Nth power of 2 n=1 2 3 4 5 6 7 8…… Bits =2 4 8 6 2 4 8 6…… 2003/4=500…… 3 So 2^2003 bits are 8; nth power of 3 n=1 2 3 4 5 6 7 8…… Bits =3 9 7 1 3 9 7 1…… 2004/4=501(…… 0) So 3^2004 bits are 18*1=8, so 2^2003*3^200...

:2004 Power of (√5-2) multiplied by 2003 power of (√5+2)

(√5-2)^2004X (√5+2)^2003
=(√5-2) X (√5-2)^2003 x (√5+2)^2003
=(√5-2) X [(√5-2) x (√5+2)]^2003
=(√5-2) X (5-4)^2003
=√5-2

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