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Find the value of the integer a, b, c satisfying -a power *(9/2)-b power *(5/3)-c power =18
(8/25)^(-A)*(9/2)^(-b)*(5/3)^(-c)=18
[2^3*5^(-2)]^(-A)*[3^2*2^(-1)]^(-b)*[5*3^(-1)]^(-c)=18
2^(-3A)*5^(2a)*3^(-2b)*2^b*5^(-c)*3^c=18
2^(-3A+b)*5^(2a-c)*3^(-2b+c)=18
18=2*3^2
-3A+b=1.(1)
2A-c =0.(2)
-2B+c=2.(3)
Solution: a=-1, b=-2, c=-2
3 To the 18th power*(-1/9th) to the 7th power
3 To the 18th power*(-1/9) to the 7th power
=-3 To the 18th power *(1/3) to the 14th power
=-3 To the 4th power ×(3×1/3) to the 14th power
=-3 To the 4th power
=-81
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