A power of 9 of 8 times b power of 10 of 9 times c power of 16 of 15 equals to 2 to obtain the value of abc respectively. A, b, c are integers

Original formula =3^(2a-2b-c)×2^(b+4c-3a-1)×5^(b-c)=1
So 2a-2b-c=0
B+4c-3a-1=0
B-c=0
Solution a=3, b=c=2

Original formula =3^(2a-2b-c)×2^(b+4c-3a-1)×5^(b-c)=1
So 2a-2b-c=0
B+4c-3a-1=0
B-c=0
Solution: a=3, b=c=2

Original formula =3^(2a-2b-c)×2^(b+4c-3a-1)×5^(b-c)=1
So 2a-2b-c=0
B+4c-3a-1=0
B-c=0
Solve a=3, b=c=2

If the integer a, b, c is equal to 8, then the value of a, b, c is

Answer:(50/27)^a*(18/25)^b*(9/8)^c=4, i.e.(2^(a+b)*3^(2b+2c)*5^(2a))/(2^(3c)*3^(3a)*5^(2b))=2^2, so there are equations: a+b-3c=2 2B+2c=3a2a=2b: a=4, b=4, c=2

A:(50/27)^a*(18/25)^b*(9/8)^c=4, i.e.:(2^(a+b)*3^(2b+2c)*5^(2a))/(2^(3c)*3^(3a)*5^(2b))=2^2, so there are equations: a+b-3c=2 2B+2c=3a2a=2b: a=4, b=4, c=2

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