Given that the three sides a, b, c of triangle ABC satisfy the absolute value of a2+b (c-1)-2 equals 10a-2√(b-4)-22, what triangle is triangle ABC? Given that the three sides a, b, c of triangle ABC satisfy the absolute value of a2+b (c-1)-2 equal to 10a-2√(b-4)-22, what triangle ABC is?

Given that the three sides a, b, c of triangle ABC satisfy the absolute value of a2+b (c-1)-2 equals 10a-2√(b-4)-22, what triangle is triangle ABC? Given that the three sides a, b, c of triangle ABC satisfy the absolute value of a2+b (c-1)-2 equal to 10a-2√(b-4)-22, what triangle ABC is?

Wrong, right?
Right -2√(b-4) should be 2√(b-4)
(A^2-10a+25)+[(b-4)-2√(b-4)+1](c-1)-2|=0
(A-5)^2+[√(b-4)-1]^2+|√(c-1)-2|=0
So a-5=0,√(b-4)-1=0,√(c-1)-2=0
A=5, b=5, c=5
So it's an equilateral triangle.

If (a-b)2 b-c|=0 is known as the triangle ABC trilateral a, b, c, then the shape of △ABC is () A. obtuse triangle B. Right triangle C. Equilateral triangles D. None of the above is correct If (a-b)2 b-c|=0, then the shape of △ABC is () A. obtuse triangle B. Right triangle C. Equilateral triangles D. None of the above is correct

According to the properties of non-negative numbers, a-b=0, b-c=0,
Solve to a=b, b=c,
So a=b=c,
So,△ABC is an equilateral triangle.
Therefore, C.