If a, b, c denote the length of the triangular abc, and the circumference of the triangular abc is 2, then the absolute value of a-b-c + the absolute value of b-c-a + the absolute value of c-a-b =?

If a, b, c denote the length of the triangular abc, and the circumference of the triangular abc is 2, then the absolute value of a-b-c + the absolute value of b-c-a + the absolute value of c-a-b =?

It can be seen that there are
B+c > a
C+a > b
A+b > c
Therefore, the original formula = b+c-a+a+c-b+a+b-c=a+b+c=2

We know that in the triangle
B+c > a
C+a > b
A+b > c
Therefore, the original formula = b+c-a+a+c-b+a+b-c=a+b+c=2

Given that BC is two fixed points, the absolute value of BC =6 and the perimeter of ABC of the triangle =16, find the trajectory of the fixed point

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