Given that abc is the three-sided length of the triangle ABC, the absolute value of the formula a-b-c is reduced to the absolute value of b-a-c

Given that abc is the three-sided length of the triangle ABC, the absolute value of the formula a-b-c is reduced to the absolute value of b-a-c

Because the triangle 2 side difference is less than the third side
Triangle 2 sides and greater than 3rd side
So a-c < b < a+c
|A-b-c c-b|=|(a-c)-b (a+c)-b|
=B-a+c+a+c-b
=2C

Because the triangle 2 side difference is less than the third side
Triangle 2 sides and greater than 3rd side
So a-c < b < a+c
|A-b-c c-b|=|(a-c)-b (a+c)-b|
= B-a+c+a+c-b
=2C

Given that the circumference of the triangle ABC is 18, the absolute value of AB=8, find the trajectory equation of the fixed point C RT, hurry! Given that the circumference of triangle ABC is 18, absolute value of AB=8, find the trajectory equation of fixed point C RT, hurry!

AC+BC=10> AB,
Therefore, the trajectory of C is an ellipse excluding (-5,0) and (5,0): c=4, a=5, b=3. The trajectory equation is: x2/25+y2/9=1(x=±5)