If a.b represents a rational number and satisfies the absolute value of the square of (a+b)+b-2=0, then the square of a is equal to?

If a.b represents a rational number and satisfies the absolute value of the square of (a+b)+b-2=0, then the square of a is equal to?

Square of (a+b)+ absolute value of b-2=0
Notes: a+b=0 and b-2=0
I.e. a=-2, b=2
A^b=(-2)^2=4

And two irrational numbers for 6

Many, characterized by irrational numbers, one for a and the other for 6-a
"6+Root 2" and "Negative Root 2"
These two irrational numbers are divided into rational number part and irrational number part respectively. As long as the irrational number part is opposite to each other, the rational number part and the sum are 6.
Example 6 2 and -√2

Many, characteristic of them, are irrational numbers, one one for 6-a
"6+Root 2" and "Negative Root 2"
These two irrational numbers are divided into rational number part and irrational number part. As long as the irrational number part is opposite to each other, the rational number part and the rational number part are 6.
Example 6 2 and -√2