2 To the 2007th power-2 to the 2006th power-2 to the 2005th power -.2 to the second power-2-1

2 To the 2007th power-2 to the 2006th power-2 to the 2005th power -.2 to the second power-2-1

It should be 1 because the first number is twice as many as the second, so the former minus the latter gets the latter, and so on, the 2007 power of 2 minus the 2006 power of 2 gets the 2006 power of 2 minus the 2006 power of 2, the 2005 power of 2 gets the 2005 power of 2 to the last -2-1 is the 1 power of 2 minus the 0 power of 2, and the last is the 0 power of 2, so the last is 1.

If the square of m+m-1=0, then the square of md3+2m+2010=——.

M2+m-1=0
So m^2=1- m m^2+ m =1 is useful after these two expressions
M^3+2m^2+2010
=M^2*(m+2)+2010(1st expression)
=(1-M)(m+2)+2010
=-M^2-m+2+2010
=-1+2+2010(Second expression)
=2011