The square of X-13X+1=0, find the number of one fourth of the fourth power of X The square of X-13X+1=0, find the number of digits of the fourth power of X * one fourth power of X

The square of X-13X+1=0, find the number of one fourth of the fourth power of X The square of X-13X+1=0, find the number of digits of the fourth power of X * one fourth power of X

X^2-13X+1=0 deformable to X+1/X=13
Square X^2+1/X^2+2=169
X^2+1/X^2=167
Then X^4+1/X^4+2 is 9 and X^4+1/X^4 is 7

If the square of X is -13x +1=0, what is the number of digits of x to the fourth power + x to the negative fourth power? Please elaborate,

If the square of X is -13x +1=0
Then x-13+1/x=0
X+1/x=13
Square on both sides x^2+2+1/x^2=169
X^2+1/x^2=167
Square both sides x^4+2+1/x^4=167^2
X^4+x^(-4)=27887
Therefore, the digit number is 7
I hope I can help you. I wish you progress in learning.

If the square of X is -13x +1=0
Then x-13+1/x=0
X+1/x=13
Square on both sides x^2+2+1/x^2=169
X^2+1/x^2=167
Square both sides x^4+2+1/x^4=167^2
X^4+x^(-4)=27887
Therefore, the digit number is 7.
I hope I can help you. I wish you progress in your study.