If the position of rational number on the number axis is as shown in the figure ------ c -- b --------0---- a --→ Trial simplification: c a-b c b =

If the position of rational number on the number axis is as shown in the figure ------ c -- b --------0---- a --→ Trial simplification: c a-b c b =

According to the figure: c < b <0< a;
A+c <0;a-b>0; b+c <0;
Original formula=-a-c+a-b-(-b-c)
=-B-c+b+c
=0;
I'm happy to answer,skyhunter002.
If there's anything you do n' t understand,

According to the figure: c < b <0< a;
A+c <0;a-b>0; b+c <0;
Original formula=-a-c+a-b-(-b-c)
=-B-c+b+c
=0;
I'm happy to answer your questions,skyhunter002 answer them
If you have any questions you can ask,

If the positions of rational numbers a, b and c on the number axis are as shown in the figure, and -------b -----a ------ A --------0-------- c -------B -----> If the position of rational numbers a, b, c on the number axis is shown in the figure, and d=|a+b|-|-2-b|-5, try to find the value of 7(d+2C)^2+2(d+2c)-5(d+2c)^2-3(d+2c).

If the position of rational numbers a, b and c on the number axis is as shown in the figure:
And d=|a+b|-|-2-b|-|a-2c|-5, find
7(D+2c)2+2(d+2c)-5(d+2c)2-3(d+2c).
By known: a+b <0,-2-b>0, a-2c <0
D=-a-b+2+b+a-2c-5
=-3-2C
D+2c=-3
7(D+2c)2+2(d+2c)-5(d+2c)2-3(d+2c)
=2(D+2c)2-(d+2c)
=2×(-3)2-(-3)
=2×9+3
=18+3
=21
I don't know if it's right ==