Given that the absolute value of a-1 plus the absolute value of b+2 is equal to 0, obtain the value of (a+b) plus the power of 2012 plus (a+b) plus the power of 2011 plus (a+b)

Given that the absolute value of a-1 plus the absolute value of b+2 is equal to 0, obtain the value of (a+b) plus the power of 2012 plus (a+b) plus the power of 2011 plus (a+b)

The absolute value of a-1 plus the absolute value of b+2 is known to be equal to 0,
A-1=0 a =1
B+2=0 b=-2
2012 Power of (a+b) and 2011 power of (a+b).
=(1-2)2012 Power plus (1-2)2011 power plus (1-2)
=1-1+1-1+…… +1-1
=0

The absolute value of a-1 plus the absolute value of b+2 is known to be equal to 0,
A-1=0 a =1
B+2=0 b=-2
2012 Power of (a+b) and 2011 power of (a+b).
=(1-2) For 2012 plus (1-2) for 2011 plus (1-2)
=1-1+1-1+…… +1-1
=0

When x =-5, the value of ax to the 2011th power - bx to the 2009th power - cx to the 2007th power +6 is -2, and when x =5, the value of this algebra When x =-5, the value of ax to the 2011th power - bx to the 2009th power - cx to the 2007th power +6 is -2. When x =5, the value of this algebra

When x=-5ax to the 2011 power -bx to the 2009 power -cx to the 2007 power +6 value is -2(-5)^2007[ a (-5)^4-b (-5)2-c ]+6=-2-5^2007(a*5^4-b*52-c ]=-85^2007(a*5^4-b*52-c ]=8 When x=5, the original formula =5^2007(a*5^4-b*52-c ]+6=8+6=14...