The position of rational number a b c on the number axis is shown in the figure: ——B——a——-1——0——c—1 (1) Compare the sizes of |a|, b, c (use < connection) (2) If m=|a+b|-|b-1|-|a-c|, find the value of the power of 2013 of 1-2012*(m+c) (3) If 2=-2, b=-3, c=3/2, and the corresponding points of a, b, c are A, B, C respectively, ask whether there is a point P on the number axis, so that the distance between P and A is 1/3, if so, request the rational number corresponding to point P, if not, explain the reason. The process must be complete and urgent (3) A=-2, b=-3, c=3/2, and the corresponding points of a, c are A, B, respectively. If it exists, request the rational number corresponding to point P. If it does not exist, explain the reason. The process must be complete.

The position of rational number a b c on the number axis is shown in the figure: ——B——a——-1——0——c—1 (1) Compare the sizes of |a|, b, c (use < connection) (2) If m=|a+b|-|b-1|-|a-c|, find the value of the power of 2013 of 1-2012*(m+c) (3) If 2=-2, b=-3, c=3/2, and the corresponding points of a, b, c are A, B, C respectively, ask whether there is a point P on the number axis, so that the distance between P and A is 1/3, if so, request the rational number corresponding to point P, if not, explain the reason. The process must be complete and urgent (3) A=-2, b=-3, c=3/2, and the corresponding points of a, c are A, B, respectively. If it exists, request the rational number corresponding to point P. If it does not exist, explain the reason. The process must be complete.

(1) B (2) m=-a-b-(1-b)+a-c=-1-c, i.e. m+c=-1, so the original formula=1-2012*(-1)=2013
(3) Should be a=-2? The phrase "make P 1/3 of the distance from A "! Please check the original question.

The position of rational numbers a, b, c on the number axis is shown in the figure. ___ C______b__o_____a

C <0
|C|=-c
C <0, b <0
So c+b <0
|C+b|=-c-b
C so c-a <0
|C-a|=a-c
B <0,a>0
A is farther from 0 than b is from 0
So |a|>|b|
So a >-b
B+a >0
| N+a|=b+a
Therefore, the original formula =-c-(-c-b)+(a-c)-(b+a)
=-C+c+b+a-c-b-a
=-C