It is shown that the power of 1992 in 1991+ the power of 1994 in 1993+ the power of 1996 in 1995+ the power of 1998 in 1997+ the power of 2000 in 1999 can be divided by 5.

1991^1992+1993^1994+1995^1996+1997^1998+1999^2000
The single digit of 1991-1992 must be 1,
In that same way,
The single digit of 1995-1996 must be 5,
The single digit for 1997-1998 must be 7.
The single digit for 1999-2000 must be 9
1+3+5+7+9=25,
So in the end, the single digits must be five,
Therefore, the above formula must be divisible by 5

What is the 365th power of 1.01 and 0.99?

1.01^365=37.78
0.99^365=0.0255
Every day,365 days?

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