A=8-b c=ab-16 how many are a, b, c (abc is a rational number) A=8-b c=ab-16 Ask how much a, b, c are (abc is a rational number)

A=8-b c=ab-16 how many are a, b, c (abc is a rational number) A=8-b c=ab-16 Ask how much a, b, c are (abc is a rational number)

Given that a, b, c are rational numbers and satisfy a=8-b, c^2=ab-16, find the value of a, b, c,
Bring a=8-b into the second formula
C^2= b (8-b)-16
C^2=8b-b^2-16
=-(B^2-8b+16)
=-(B-4)^2
Because c^2>=0 and (b-4)^2>=0
So, above all,
B-4=0
B=4
So c=0 a=4

Can the power of 2012-5 times 7 and the power of 2011-3 times 7 and the power of 2010 be divided by 11?

The power of 2012-5 of 7 multiplied by 7 the power of 2011-3 of 7 multiplied by 7 the power of 2010=72x7 the power of 2010-5x7x7 the power of 2010-3x7 the power of 2010=(49-5x7-3) x7 the power of 2010=11x7 the power of 2010(the power of 2012-5 of 7 multiplied by 7 the power of 2011-3 multiplied by 7 the power of 2010)÷11=11=11x7 the power of 2010÷11=...