If the quadratic of (a-1) and the absolute value of b+2 are mutually opposite, then the 2012th power of (a+b)=

From the meaning of the title
(A-1)2+|b+2|=0
A-1=0 a =1
[±(B+2)]=0 b=-2
(A+b)^2012
=[1+(-2)]^2012
=(-1)^2012
=1

From the meaning
(A-1)2+|b+2|=0
A-1=0 a =1
[±(B+2)]=0 b=-2
(A+b)^2012
=[1+(-2)]^2012
=(-1)^2012
=1