Try to show that the difference between two rational numbers is still rational.

Try to show that the difference between two rational numbers is still rational.

Since any rational number can represent the component number form a/b (a, b is an integer and b=0)
Then for any two rational numbers a/b (a, b is an integer and b=0) and c/d (c, d is an integer and d=0)
A/b-c/d=(ad-bc)/bd
Clearly (ad-bc) and bd are integers, and bd =0,
Then (ad-bc)/bd is rational
This proves that the difference between any two rational numbers is a rational number
I won't be able to talk there.

The sum of two rational numbers is greater than the difference between the two numbers It was "inevitable ""very likely"" possible ""unlikely"" impossible" The sum of two rational numbers is greater than the difference between the two numbers It's "inevitable "," probable "," unlikely "," impossible"

Perhaps.
That's what I personally think.
After all, the question did not say whether it was A-B or B-A

Likely.
That's what I personally think.
After all, the title didn't say A-B or B-A.