In (-1)2007,|-1|3,-(-1)18(-1)18,18, negative numbers are () A. One B.2 Nos. C.3 Nos. D.4 Nos. In (-1)2007,|-1|3,-(-1)18(-1)18,18, negative numbers have () A. One B.2 Nos. C.3 Nos. D.4 Nos.

In (-1)2007,|-1|3,-(-1)18(-1)18,18, negative numbers are () A. One B.2 Nos. C.3 Nos. D.4 Nos. In (-1)2007,|-1|3,-(-1)18(-1)18,18, negative numbers have () A. One B.2 Nos. C.3 Nos. D.4 Nos.

A,(-1)2007=-1<0
B,|-1|3=1>0
C.-(-1)18=-1<0
D,18>0
There are two negative numbers
Therefore, B.

Given rational number abc satisfies /a-1/+|b+3||3c-1|=0, find the value of (abc)125th power/(a4*b3*c2) Given rational abc satisfies /a-1/+|b+3||3c-1|=0, find the value of (abc)125th power /(a4*b3*c2)

/A-1/+|b+3||3c-1|=0
So a-1=b+3=3c-1=0
So a=1, b=-3, c=1/3
Then abc=-1
Therefore, the original formula =-1/(1*(-27)*1/9)=3