It is calculated by simple method:(1)、1/4 of four thousand and five times 16 of two thousand and three times (2)8(5χ+3/2)(5/2χ-3/4)

It is calculated by simple method:(1)、1/4 of four thousand and five times 16 of two thousand and three times (2)8(5χ+3/2)(5/2χ-3/4)

(1)[(1/4)^4005]/(16^2003)=[1/(4^4005)]*(4^2)^2003=(4^4006)/(4^4005)=4
(2)8(5X+3/2)[(5/2) x)-3/4]=16[(5/2) x)+3/4][(5/2) x-3/4]
=16[(25/4) X^2-9/16]=100 x^2-9

Consider the following equation: the first power of 2 equals 2, the second power of 2 equals 4, the third power of 2 equals 8, the fourth power of 2 equals 16, and the fifth power of 2 equals 32,2 Look at the following equation: the first power of 2 equals 2, the second power of 2 equals 4, the third power of 2 equals 8, the fourth power of 2 equals 16, the fifth power of 2 equals 32, the sixth power of 2 equals 64, the seventh power of 2 equals 128, the eighth power of 2 equals 256... What is the end-of-2010 mantissa of 2?

The law is that the exponent is a multiple of 1,2,3,4, and the law of multipliers is that after dividing:2,4,8,6.2010 by 4, the remainder is 2, which means that his number of bits should be the second, that is,4

The law is that the exponent is a multiple of 1,2,3,4, and the law of multipliers is that after dividing:2,4,8,6.2010 by 4, the remainder is 2, indicating that his number of bits should be the second, that is,4