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What does the scalar product and vector product mean? Thank you, God.
Let A, B be two vectors, and the angle from A to B be θ. Then A*B=" A ""B "cosθ is their inner product, dot product, and quantity product. A×B=" A"" B" sinθ is their outer product, cross product, and vector product. The geometric meaning of quantity product is that the projection length of one vector on the other vector is multiplied by the length of the other vector. The geometric meaning of vector product is that it is a vector perpendicular to A, B. Its size is equal to the area of the parallelogram surrounded by these two vectors, and its direction is determined by the right-hand rule.
Polar and scalar vectors Distinction and Connection Is the difference between a polar vector and an axial vector Polar and scalar vectors Distinction and connection Is the difference between a polar vector and an axial vector
Good morning question. Try to answer it.
Polar is a circular coordinate system
Plane coordinate system
2D~
3D Similar
Is the square of the vector equal to the square of the module of the vector?
Absolutely necessary...
The Law of Angular Momentum Proves Why Time Vector v × Vector p is Equal to 0
P=mv and v are parallel vectors, so cross multiplication is zero.
Vector operation 1. In the quadrilateral ABCD, AB=2a-3b, BC=-8a+bCD=-10a+4b, and a and b are not collinear vectors, the shape of the quadrilateral ABCD is judged and the reason is explained. 2. In any quadrilateral ABCD, E is the midpoint of AD and F is the midpoint of BC. The letters in these two questions are vectors. Could you explain it to me, and, uh, could you not use a special quadrilateral for the second passage?
1.
AD=AB+BC+CD=-16a+2b=2BC
So AD is parallel to BC and AD is twice as long as BC
So ABCD is trapezoidal.
That should be the only conclusion that can be drawn.
2.
Let AB=a, BC=b, CD=c (both directives)
So AD=a+b+c
Because ED=AD/2, CF=CB/2
So ED=(a+b+c)/2, CF=-b/2
So EF=ED+DC+CF=(a+b+c)/2-c-b/2=(a-c)/2=(AB-CD)/2=(AB+DC)/2
It's not the same conclusion as the title, but the process must be right.
There must be a problem with the problem
Topic of Vector Operation Given that o is the outer center of triangle ABC, AB is equal to 4AC is equal to 6BC is equal to 8, calculate the product of AO vector and BC vector. Topic of Vector Operation Given that o is the outer center of the triangle ABC, AB equals 4AC equals 6BC equals 8, how to calculate the product of AO vector and BC vector? Topic of Vector Operation Given that o is the outer center of triangle ABC, AB is equal to 4AC is equal to 6BC is equal to 8, how to calculate the product of AO vector and BC vector?
It should be AB=4, AC=6, BC=8. Then the correct method for this problem should be: AO=AC-OC, AO=AB-OB, so AO=1/2(AC-OC+AB-OB), then AO*BC, then O is the outer center,(OC+OB)*BC=0 encountered in the reduction process, so the final reduction is 1/2(AC*BC+AB*BC), using the cosine theorem, the final result is 10
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