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Given the coordinates of two points A and B, find the coordinates of vector AB and BA:1.A (3,5), B (5,6)2.A (-3,5) Given the coordinates of two points A and B, find the coordinates of vector A, B and BA: 1.A (3,5), B (5,6) 2.A (-3,5), B (3,2) 3.A (0,5), B (0,2) 4.A (4,0), B (9,0)
Vector AB is the coordinates of B minus the coordinates of A vector BA is A minus B
1: AB (2,1) BA (-2,-1)
2: AB (6,-3) BA (-6,3)
3: AB (0,-3) BA (0,3)
4: AB (5,0) BA (-5,0)
Is the coordinate of the last point minus the coordinate of the first point.
The vector AB is the coordinate of B minus the coordinate vector of A, and the vector BA is A minus B.
1: AB (2,1) BA (-2,-1)
2: AB (6,-3) BA (-6,3)
3: AB (0,-3) BA (0,3)
4: AB (5,0) BA (-5,0)
Is the coordinate of the last point minus the coordinate of the first point.
Given point A (-1,-5) and vector a =(2,3), if A B =3a, what is the coordinate of point B? Please write down the steps
Set B (X, Y)
AB=(X+1, Y+5)=3a
X+1=3*2
Y+5=3*3
Get: X=5 Y=4
If the vector a, b is a non-zero vector, t=R, if the starting points of the vectors a, b are the same, what is the value of t? The vector a, ta,1/3(a+b) ends on the line If the vector a, b is a non-zero vector, t=R,(1) if the starting points of the vectors a, b are the same, what is the value of t, and the terminal point of the vector a, ta,1/3(a+b) is on the straight line (2) if the absolute value a=b and the angle between the vector a and b is 60, the value of the absolute value of t is the smallest.
(1) Let a=(x1, y1), b=(x2, y2), then there is tb=(t*x2, t*y2),1/3(a+b)=(1/3(x1+x2),1/3(y1+y2)). Since the trivector endpoint is collinear, then there is a real number N such that tb-a=N (1/3(a+b)-a), i.e., tx2-x1=N (1/3(x1+x2)-x1) ty2-y1=N (1/3(y1+y2)-y1), and the solution N can be 2/3...
If two equal vectors have the same start point, then their end points are the same? If two equal vectors have the same starting point, then their ends are the same?
If the vectors are equal, the module and direction angle are equal
A sufficient condition for two vectors to be equal is that they have the same starting point and the same ending point. Doesn't the same start and end mean the same direction?
It is necessary that the starting point and the ending point are different without affecting the equality of the vectors.The vectors starting from different starting points only need the same direction and the modules are equal to each other to deduce the equality of the two vectors.
It is necessary that the starting point and the ending point are different, which does not affect the equality of the vectors.
Equal vector, if the starting point is different, the end point must be different! If the zero vector, the starting point and the ending point coincide, but I don't understand why, seek expert guidance Equal vectors. If the starting point was different, then the ending point must be different! If the zero vector, the starting point, and the ending point coincide, but I don't know why at all, to seek the guidance of an expert
If the two vectors are zero vectors, their starting points are different, then their ending points are different.(Only their ending points are the same as their starting points). So "the same vector, if the starting points are different, then the ending points must be different!" That's right! I hope you are satisfied with my answer!
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