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Known A =(2,-1), B=(λ,3), if A and If the angle of b is obtuse, the value range of λ is ___.
0
Given the vector a=(λ,2λ), b=(3λ,2), if the angle between a and b is acute, then the value range of λ is
Because the included angle of a, b is acute angle, cosa >0 ab >0=(enter, enter)(3 enter,2)
=3 To ^2+4 to >0 to >-4/3
Given vector m=(a, b), n=(c, d), p=(x, y), define new operation m*n=(ac+bd, ad+bc) Where, on the right side of the equation is the ordinary addition and multiplication operation, for any vector m, there is m*p=m, then the vector P is A.(1,0) B.(-1,0) C.(0,1) D.(0,-1)
(A) Correct
The vector method is used to prove that if AB⊥CD, AD⊥BC, AC⊥BD.
I don't know how to use vector symbols. I just use the word "vector ". Does it look a little troublesome? Without the word "vector ", the vector AB=vector a, vector AD=vector b, vector AC=vector c AB CD vector AB·vector CD=0, i.e. vector AB·(vector AD-vector AC)=0 vector a·(vector c-...
I don't know how to use vector symbols. I just use the word "vector ". Does it look a little troublesome? The vector AB= vector a, vector AD= vector b, vector AC= vector c AB CD vector AB·vector CD=0, i.e. vector AB·(vector AD-vector AC)=0 vector a·(vector c-...
As shown in the figure, in triangle ABC, AD⊥AB, vector BC=root number 3 vector BD,|vector AD|=1, then vector AC*vector AD=
I'll take it as a dot.
Multiply mutually perpendicular vector points by 0
Vector AC* Vector AD
=(Vector AB + vector BC)* vector AD
= Vector AB * vector AD + vector BD * vector AD with 3 times root number
=3 Times the root number (vector AD - vector AB)* vector AD
=|Vector |^2 of 3 times root |^2
=Root 3
I'll take it as a dot...
Multiply mutually perpendicular vector points by 0
Vector AC* Vector AD
=(Vector AB + vector BC)* vector AD
= Vector AB * vector AD + vector BD * vector AD of 3 times root number
=3 Times the root number (vector AD - vector AB)* vector AD
=|Vector |^2 of 3 times root |^2
=Root 3
As shown in the figure, in △ABC, AD⊥AB, vector BC = root number 3 vector BD, the modulus of vector AD is equal to 1, then what is the vector AC multiplied by vector AD equal to Thank you. If you can, please tell me how to do these questions.
From AB Vertical AD
Vector AB multiplied by vector AD =0;(hereinafter,* is the multiplication between vectors)
Vector AC * Vector AD =(Vector AB + Vector BC)* Vector AD = Vector AB * Vector AD + Vector BC * Vector AD =0+(Root 3 Vector BD)* Vector AD = Root 3(Vector BA + Vector AD)* Vector AD = Root 3 Vector BA * AD + Root 3 Vector AD * Vector AD =0+ Root 3*1= Root 3
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