Ab is a non-zero vector and |a+b|=|a||b|, Then A: a is parallel to b, and a and b have the same direction B.a=b C.a=-b D. None of the above is correct Ab is a nonzero vector and |a+b|=|a||b|, Then A: a is parallel to b, and a and b have the same direction B.a=b C.a =-b D. none of the above Ab is a nonzero vector and |a+b|=|a||b|, Then A: a is parallel to b, and a and b have the same direction B.a=b C.a=-b D. None of the above is correct

Ab is a non-zero vector and |a+b|=|a||b|, Then A: a is parallel to b, and a and b have the same direction B.a=b C.a=-b D. None of the above is correct Ab is a nonzero vector and |a+b|=|a||b|, Then A: a is parallel to b, and a and b have the same direction B.a=b C.a =-b D. none of the above Ab is a nonzero vector and |a+b|=|a||b|, Then A: a is parallel to b, and a and b have the same direction B.a=b C.a=-b D. None of the above is correct

Ab is a non-zero vector and |a+b|=|a||b|,
Then: a, b in the same direction
Option A

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Ab is a nonzero vector and |a+b|=|a||b|,
Then: a, b in the same direction
Option A

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Given the module of vector a=5, the module of vector b=4a, the included angle of vector b=π/3, find the modules of (a+b)×a and a+b

Ab=5*4*(1/2)=10
(A+b) a=a^2+ab=25+10=35
|A+b|^2=a^2+2ab+b^2=25+20+16=61
|A+b|=√61

Given the module of vector a=2 the module of vector b=5, vector a multiplies vector b=-3, finds the module of vector a+vector b and the module of vector a-vector b Given that the module of vector a is 2, the module of vector b is 5, vector a is multiplied by vector b is -3, and the module of vector a+vector b and the module of vector a-vector b are obtained

Module of vector a + vector b = square of root (vector a + vector b)= root (2*2+2*(-3)+5*5)= root 23
The latter = square of the root (vector a-vector b)= root (2*2-2*(-3)+5*5)= root 35

The module length of vector a=5, the module length of vector b=4, the module length of vector c=3, the angle between vector a and vector b is 60 degrees, the angle between vector a and vector c is 4... The module length of vector a =5, the module length of vector b =4, the module length of vector c =3, the angle between vector a and vector b is 60 degrees, the angle between vector a and vector c is 45 degrees, and the angle between vector b and vector c is 30 degrees.

A*b=|a||b|cos60=10a*c=|a||c|cos45=15 root number 2/2b*c=6 root number 3(a+b+c)^2=a^2+b^2+c^2+(a*b+a*c+b*c)=70+15 root number 2+12 root number 3|a+b+c|=root number [70+15 root number 2+12 root number 3] Set the angle between a+b and a+c as w|a+c|=root number (34+15 root number 2)...

Given that the angle between vectors a and b is 120 degrees, the module of vector a is one, the module of vector b is three, and the module of vector a minus vector b is 5 times

Ab=|a*|b|*cos120°=1*3*(-1/2)=-3/2
|5A-b |^2=25a^2+b^2-10ab
=25*1+3^2-10*(-3/2)
=25+9+15
=49
|5A-b|=√49=7

Ab=|a*|b|*cos120°=1*3*(-1/2)=-3/2
|5A-b|^2=25a^2+b^2-10ab
=25*1+3^2-10*(-3/2)
=25+9+15
=49
|5A-b|=√49=7

Given that a, b are two non-zero vectors, and a-3b is perpendicular to 7a+5b, and a+4b is perpendicular to 7a+2b, find the angle between a and b? Rt

A-3b is perpendicular to 7a+5b, and a+4b is perpendicular to 7a+2b, then (a-3b)•(7a+5b)=0 7-16A-15b=0... 1(A+4b)•(7a+2b)=0 7+3+8=0... ②②-①:46A | B+23|...

(A-3b)•(7a+5b)=0 if a-3b is perpendicular to 7a+5b and a+4b is perpendicular to 7a+2b 7|A|2-16a•b-15|b|2=0... 1(A+4b)•(7a+2b)=0 7|A|2+30a•b+8|b|2=0... ②②-①:46A•b+23|...