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Is the zero vector perpendicular to the zero vector According to the textbook of Tongji University, zero vector is perpendicular to all vectors.
Not perpendicular, originally defined as zero vector perpendicular to any non-zero vector
Not perpendicular, originally defined as zero vector and any non-zero vector perpendicular
Vector e is a nonzero vector, if vector AB=2e, vector CD=-3e, and |vector AD|=|vector BC|, then quadrilateral ABCD is
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How to define the multiplication of vectors? What is the concept of quantity product?
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What is the difference between vector product and quantity product?
The result of the quantity product is a numerical value, and the result of the vector product is still a vector.
The Problem of Quantity Product of Vector 1. Is the multiplication of two vector points obtained by number, and the number and vector can not be multiplied by point? 2. How to express the image of |a||b|cosa 3. How to prove (λa)·b=λ(a·b)=a·(λb) by image? The Problem of Quantity Product of Vector 1. Is the multiplication of two vector points obtained by number, and the number and vector can not be multiplied by points 2. How to express the image of |a||b|cosa 3. How to prove (λa)·b=λ(a·b)=a·(λb) by image? The Problem of Quantity Product of Vector 1. Is the multiplication of two vector points obtained by number, and the number and vector can not be multiplied by points? 2. How to express the image of |a||b|cosa 3. How to prove (λa)·b=λ(a·b)=a·(λb) by image?
This is the basic concept, point multiplication is the operation of two vectors, the result is number.(So also called "number product ") Number and vector of course is not" point multiplication ".
This is the basic concept. Point multiplication is the operation of two vectors and the result is number.(So it is also called "number product ") Number and vector can not be" point multiplication ".
Given a=(2,1) b=(1,-3), c=(3,5), take a, b as a set of bases, and use a, b to indicate that the c vectors are all vectors
Let c=xa+yb,(where x, y are real numbers)
I.e.(3,5)= x (2,1)+ y (1,-3)
Then 3=2x+y,5=x-3y.
X=2, y=-1.
C=2a-b.
Let c=xa+yb,(where x, y are real numbers)
I.e.(3,5)= x (2,1)+ y (1,-3)
Then 3=2x+y,5=x-3y.
The result is x=2, y=-1.
C=2a-b.
Let c=xa+yb,(where x, y are real numbers)
I.e.(3,5)= x (2,1)+y (1,-3)
Then 3=2x+y,5=x-3y.
The result is x=2, y=-1.
C=2a-b.
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