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If the starting point A of vector a is (-2,4) and the ending point B is (2,1), find the unit vector perpendicular to the module (2) of (1) vector a and vector a
1) Vector a=(2--2,1-4)=(4,-3)|a|=√(4^2+(-3)^2)=52) Let unit vector b=(cosb, sinb) ab=4 cosb-3 sinb=0, so cosb=3/5 or -3/5 sinb=4/5 or -4/5 is unit vector (3/5,...
Given vector a=(-2,3), vector b runs parallel to a, and vector b starts at (1,2)(1,2), and the ending point B is on the coordinate axis, then the coordinate of B is I have solved the equation 3X+2Y-7 for vector b =0 Ask for guidance Given vector A=(-2,3), vector B runs parallel to A, and the starting point of vector B is (1,2), and the ending point B is on the coordinate axis, then the coordinate of B is I solved the equation for vector B 3X+2Y-7=0 Ask for guidance
Let B be (x, y)
(X-1)/-2=(y-2)/3
3X-3=-2y+4
3X+2y-7=0
Y =7/2 when x =0
X =7/3 when y =0
B (0,7/2) or B (7/3,0)
Given a vector a=(3,1) starting with p (1,3), the coordinates of its end point b are Given vector a=(3,1) with p (1,3) as the starting point, the coordinate of its end point b is
B (4,4)
Let a vector, b vector is not collinear, if a vector, tb vector,1/3(a vector + b vector), and the end point is on the same line, then t=?
A, tb,(a+b)/3 ends on the same line
I.e. a-tb is collinear with a-(a+b)/3
I.e. a-tb=k (2a/3-b/3), i.e. k (2a-b)=3a-3tb
I.e.2k=3, i.e. k=3/2, therefore:3t=k, i.e. t=k/3=1/2
Given that vectors a, b are not collinear, a, b, c have a common starting point, and c=ma+nb, if the ending points of a, b, c are on the same straight line, prove: m+n=1. Let A and B be two points on the straight line l, O be a point outside the straight line, and for any point P on l, if there is a real number x y, so that vector OP=x vector OA+y vector OB, prove x+y=1.
Hello: Actually, the two propositions you need to prove are the same in essence, so I will prove one of them. This is a small theorem of 3-point collinear. I take the second one you ask as an example: Let's suppose that the left-to-right order of 3 points on the line L is point A, point B, point P. Then, vector AB = vector OB - vector OA factor...
Can the unit vector of a non-zero vector be reversed from the non-zero vector? RT
Not allowed
The unit vector is parallel to the same direction and can not be reversed
No. No.
The unit vector is parallel to the same direction and can not be reversed
Not allowed
The unit vector is parallel to it in the same direction and can not be reversed
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