Is the module of an equal vector equal

Is the module of an equal vector equal

Equal

Find the vector whose angle is equal to the vector a=(7/2,1/2), b=(1/2,7/2) and whose modulus length is 1 Find the vector equal to the included angle of vector a=(7/2,1/2), b=(1/2,7/2), and the module length is 1

Let c=(m, n),
|C |=√(m^2+n^2)=1,
Let the angle between vectors a and c be θ
Cosθ=a·c/(|a||c|=(7m/2+n/2)/[√(49/4+1/4)*1]=√2(7m/2+n/2)/5,
Cosθ=b·c (/|b||c|)=(m/2+7n/2)/√[(1/4+49/4)*1]=√2(m/2+7n/2)/5,
√2(7M/2+n/2)/5=√2(m/2+7n/2)/5,
M=n,
M^2+n^2=1,
M=2/2,
N=2/2,
M, n shall be the same number
Then vector c=(√2/2,√2/2), c=(-√2/2,-√2/2),

Given |a|=2,|b|=3,|a-b|=√7, the angle between vector a and b is

|Vector a-vector b|=√7(|vector a-vector b|)^2=7(|vector a|)^2-2*vector a*vector b+(|vector b|)^2=7|vector a|=2,|vector b|=3 4-2*vector a*vector b+9=13-2*vector a*vector b=7 vector a*vector b=|vector a vector b|*cos=6 cos=3 cos=1/2 vector a and...

If |a|=2|b|=3|a-b|=√7, is the angle between vector a and vector b? To Detail the Process

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1. Given vector a=(2,2), the angle between vector b and vector a is 3π/4, and a.b=-2. (1) Find vector b (2) If t =(1,0) and b⊥t, c =(cosa,2(cosc/2)^2), where a and c are two acute angles of a right triangle, find the value of |b+c|. 2. Given plane vector a =(root 3,-1), b =(1/2, root 3/2) (1) Find a.b (2) Let c=a+(x-3) b, d=-ya+xb (where x is not equal to 0), if c⊥d, try to find the function relation y=f (x) and solve the inequality f (x)>7. Give me an explanation.....

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If |a|=1|b|=root 2 and a-b is perpendicular to a, then the angle between a and b is? (Ab is a vector)

A-b is perpendicular to a, so (a-b)*a=0
I.e. a^2-a*b=0, a^2=|a|^2=1, so
A*b=1
Cosθ=a*b/(|a||b|)=1/root2=root2/2.
Cos45°= root 2/2
So θ=45°