Draw a square with an area of 5 in a 4 * 4 grid

Draw a square with an area of 5 in a 4 * 4 grid

For the convenience of illustration, first establish a coordinate axis
The vertex of the lower left corner of your 4 * 4 grid is the origin, which is (0,0)
Find out (1,4) (0,2) (3,3) (1,2) connecting the four points

As shown in the figure, in a square grid composed of 4 × 4 small squares, the area ratio of shadow area to square ABCD is () A.3:4 B.5:8 C.9:16 D.1:2 I'm sorry you didn't draw it yourself. Thank you

What about the picture?
Oh, draw it yourself
Choose B. because you see, connect this point with this point, so these three points form a triangle. Look at that point, that point and that point form a triangle, so the shadow area of this part I drew is 10, the total area is 16, so it is 5:8

As shown in the figure, we know that the side length of the square ABCD is a. take the angle a as the common angle, draw three small squares inside the square ABCD, and change the area of the square ABCD Quartering, in AE, AF, Ag, AB these four line segments, choose any three to form a triangle, including right triangle? If yes, please list three side lengths and give proof; if not, please give reasons.

If AE is the shortest in AC, AF is the longest, AE = B, AF = C, Ag = D, then b square = (1 / 4) a square, C square - b square = (1 / 4) a square, that is, C square = (1 / 2) a square, D square - C square = (1 / 4) a square

As shown in the figure, the area of the square ABCD is 12, and △ Abe is an equilateral triangle. The point E is in the square ABCD, and there is a point P on the diagonal AC, To minimize the sum of PD + PE, the minimum value is A. 2 root sign 3 B. 2 root sign 6 C.3 D. Radical 6

It is easy to prove that point F coincides with point B, so DP = BP, so DP + PE = BP + PE because the line segment between two points is the shortest

How to divide an equilateral triangle into 2, 3, 4, 6 congruent figures respectively?

When dividing two, draw a vertical line directly
When dividing three points: in the middle of the triangle, take a point in the middle of the triangle to connect the three vertices to the point in the distance
When dividing four: point their midpoint on the two sides (not the bottom) of the equilateral triangle, and then connect them. Then point a midpoint from the bottom edge to connect with the original two key points
When dividing six: you can use the vertical lines of these three points separately!
(you can ask me if you don't understand)

As shown in the figure, divide the equilateral triangle into three congruent figures

Method 1: connect the center and vertex of equilateral triangle;
Method 2: connect the center of equilateral triangle with the midpoint of each side;
Method 3: connect the center of an equilateral triangle with a point on each side, and the distance from this point to the corresponding vertex is equal

How can a square be divided into five figures equally?

..
Five rectangular bars

As shown in the figure, a 4 * 2 rectangle can be divided into 2 small squares, 5 small squares or 8 small squares in three different ways. After a 3 * 5 rectangle is divided in different ways, the number of small squares can be

The maximum is 15
If there is one 2 × 2, it will be 12
There are two, two by two, that's nine
There is a 3 × 3, which is 7
A 3 × 3, a 2 × 2 is 4
There are four, seven, nine, twelve, fifteen

How to divide a square into five shapes of equal size

If the side length is five equal parts, it can be divided into five shapes and equal size rectangles

The square is divided into four parts, axisymmetric, with equal shape and area At present, the line connecting the midpoint of the four sides of a diagonal line is divided into a horizontal or vertical quadripartite rectangle Great Xia, just me. What else?

A set of opposite edges is connected by the midpoint, and one of them is connected with the two vertices of the opposite side