Given that 1-A of the square root of a is equal to 1-A of the root of a, what is the value range of a?

Given that 1-A of the square root of a is equal to 1-A of the root of a, what is the value range of a?

A:
√[(1-a)/a²]
=√(1-a)/|a|
=√(1-a)/a
∴a>0
And 1-A ≥ 0
∴0

If the square of the root sign (A-1) is equal to 1-A, find the value range of A

From the meaning of the title,
1-a=√(a-1)^2≥0
That is, 1-A ≥ 0,
The solution is: a ≤ 1,
Therefore, the value range of a is: a ≤ 1

If the square of the root sign (B-3) is equal to 3-B, then the value range of B is?

Because the result of the root sign is greater than or equal to 0
So 3-B ≥ 0
b≤3

The square of (a + 1) under the root sign + the square of (A-1) under the root sign is equal to 2 to find the value range of A Find the value range of a High one simple drop, do not fall, do not want to be innocent, please some detailed process, otherwise I may not understand

When a is greater than 1, the original formula is equal to 2a and greater than 2
When a is less than - 1, the original formula is equal to - 2A and greater than 2
When a is greater than or equal to - 1 and less than or equal to 1, the original formula is equal to 2
So the value range of a is greater than or equal to - 1 and less than or equal to 1

How much is one eighth of four Radix?

1/4√8
=（4√8*1）/（4√8*4√8）
=8√2/128
=√2/16

What is the cube root of root 8 plus zero minus 1 / 4 of root 8?

The cube of the following sign 8 is 8 times that of the sign 8, and a quarter of the sign is equal to half of the number. Therefore, the original formula is equal to eight times the sign eight minus one half
For adoption

B is equal to 2, C is equal to the root sign 3 plus 1, and the angle a is equal to 60 degrees

b＝2,c＝√3＋1,∠A＝60°
From the cosine theorem we can get it
a²＝b²＋c²－2bccosA
＝4＋(4＋2√3)－2(√3＋1)
＝8＋2√3－(2＋2√3)
＝6
Then, a = √ 6
So, the value of a is √ 6

If a = radical 3 + 1. B = 2, C = radical 2, then the angle c is equal to cosC=(a^2+b^2-c^2)/2ab =[(√3+1)^2+2^2-(√2)^2]/[2*(√3+1)*2] =[4+2√3+4-2]/[4(√3+1)] =[6+2√3]/[4(√3+1)] =2√3(√3+1)/[4(√3+1)] =√ 3 / 2C = 30 the answer is like this. I have a question, which is the second step in the last step. How can I see that it can be simplified by putting forward 2 radical signs 3? I don't think it can be solved (how to solve the problem of raising common factors that can't be seen at a glance)

Cannot see
Then rationalize the denominator
It's no problem

What is (- 1-radical 5) (- radical 5 + 1) equal to

Four

What is the root 45 divided by the root 1 / 5 times the root 2 and 2 / 3

Radix 45 divided by Radix 1 / 5 times Radix 2 and 2 / 3
=Radix 45 times Radix 5 times Radix 8 / 3
=Root number (45 times 5 times 8 / 3) = root number 600 = 10 times root number 6