Why is the square X of - (x-1) meaningful under the radical

Why is the square X of - (x-1) meaningful under the radical

-(x-1)²>=0
(x-1)²

What is the real number of X, the following formula is meaningful in the range of real number? (1) root sign x (2) root sign X2 (3) root sign 2 / 2 X-1 (4) root sign - (x + 2) square

X is nonnegative 2. X is nonnegative 3. X ≥ 1. 4. X is any number
My own opinion may be wrong, please forgive me

When x is what, the following formula is meaningful in the range of real numbers? Radical - 1 + 2x radical - 3x-2 radical - xsquare + 4

Greater than or equal to 0 under root sign
therefore
-1+2x≥0
x≥1/2
-3x-2≥0
x≤-2/3
-x²+4≥0
x²≤4
-2≤x≤2

The set of real numbers x that makes y = the square of root x-x-2 meaningful Descriptive method

X ≥ 2 or X ≤ - 1

When x is a real number, the following formulas are meaningful in the range of real numbers. The root sign (- x squared)

Since the root sign is - x 2, it makes sense when x = 0

If 1 / 2 of the formula (root X-2) is meaningful, the value range of X is

(X-2) 1 / 2
Or 1 / 2 of [√ (x) - 2]
The first one
If the root is greater than or equal to 0, the denominator is not equal to 0
∴x-2>0
X>2
The second kind
X ≥ 0 and X ≠ 2

The value range of X that makes 3-x meaningful is

3/√(3-x)
3-x>0
X<3

If formula If x − 3 is meaningful, then the value range of real number x is______ .

According to the meaning of the title, we get
x-3≥0，
X ≥ 3;
So the answer is: X ≥ 3

What is the value of X? The following formula is meaningful? 3-x under the root sign, 1 / 2 of X under the root sign minus 1 / x under the root sign Give me the process! It's three small questions

For X to be meaningful under the root sign, X must be greater than zero. For one part of X to be meaningful, X is not equal to zero
Therefore, the three value ranges are x0

When x______ When, X + 3 makes sense______ Equation 1 X − 3 makes sense

x+3≥0，
The solution is x ≥ - 3;
X ≥ 0 and
x-3≠0，
The solution is x ≥ 0 and X ≠ 9
So the answer is: ≥ - 3; X ≥ 0 and X ≠ 9