There are three grasslands with an area of 5, 15 and 36 hectares. The grass on the grassland is as thick and grows as fast. The first grassland can feed 12 cattle for 28 days, the second grassland can feed 21 cattle for 63 days, and the third grassland can feed 144 sheep for several days? (the amount of grass eaten by four sheep in one day is the same as that of one cow in one day)

126 days
One cow's daily grass consumption was 1 gal
12 cattle ate 12 * 28 * 1 = 336 geel in 28 days, and 336 / 5 = 67.2 geel per hectare on average;
21 cattle ate 21 * 63 * 1 = 1323 geels in 63 days, and 1323 / 15 = 88.2 geels per hectare grassland,
The growth rate of grass per hectare: (88.2-67.5) / (63-28) = 0.6 geel;
The original grass per hectare of Grassland: 67.2-0.6 * 28 = 50.4 geel
Grass on 36 ha Grassland: 50.4 * 36 = 1814.4 geel
The growth rate of grass on 36 ha Grassland: 0.6 * 36 = 21.6 geel
Therefore: 1814.4 / (144 / 4-21.6) = 126 days

There are three grasslands with an area of 5, 6 and 8 hectares respectively. The grass on the grassland is as thick and grows as fast as possible. The first grassland can feed 11 cattle for 10 days The second grassland can feed 12 cattle for 14 days. How many days can the third grassland provide for 19 cattle? Be sure to solve the equations!

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If a cow eats x ha a day and a meadow grows y ha per day, there will be 110x = 5 + 50y, 12.14x = 14.6y + 6. The solution x = 1 / 7, y = 3 / 14. If the third piece can eat t days, then 19tx = 8 + 8yt. The XY obtained by substituting the solution can solve t = 8, so it can feed for 8 days

There are three grasslands with an area of 4 mu, 8 mu and 10 mu. The grass on the grassland is as thick and grows as fast. The first grassland can feed 24 cattle for 6 weeks, and the second grassland can feed 36 cows for 12 weeks. How many weeks can the third grassland provide for 50 cattle?

Let each cow eat one portion of grass every week. We have a 1 mu grassland, which can feed 24 ／ 4 = 6 cattle for 6 weeks, 36 ／ 8 = 92 cows for 12 weeks. Then how many weeks can 50 ／ 10 = 5 cattle eat? Therefore, the annual growth of the grass was (92 × 12-6 × 6) × (12-6) = 3 (share), and the original grass (6-3) ×

The area of a triangle is 0.8 hectares. Its bottom is 400 meters. How many meters is its height?

8 ha = 8000 m2,
8000×2÷400
=16000÷400，
=40 (m);
A: its height is 40 meters

There is a triangular paddy field with an area of 2.4 hectares and a bottom of 400 meters. How many meters is its height?

2.4 HA is equal to 24000 square meters, 24000 × 2 △ 400 = 480 meters

In a triangular paddy field with an area of 1.5 hectares, its height is 300 meters, and how many meters is its bottom?

1.5 hectare = 15000 square meters, its bottom is: 15000 × 2 △ 300 = 100 meters

What is the area of a triangular paddy field with a bottom of 500 meters and a height of 250 meters? If the rice field is 7.3 tons per hectare, how many tons of rice can be harvested in this field? Give it to me now!

Area: 500 × 250 = 125000 (M2) = 12.5 (HA)
Yield: 12.5 × 7.3 = 91.25 (tons)

There is a square paddy field with an area of 1 hectare. What is the side length of this paddy field? I know the answer is 100 meters, but I don't know how to calculate it

1 ha = 10000 M2
Because 100 * 100 = 10000
So the side length is 100 meters

The farm divided 8400 kg of chemical fertilizer into three paddy fields according to the area of three paddy fields. The area of the first paddy field is 8 hectares, the second is 6 hectares, and the third is 7 hectares, How many kilograms of chemical fertilizer can you get from each of the three paddy fields? Tell me the method. Thank you!

An: 8:6:7 ratio
So the first plot of fertilizer: 8400 × 8 / (8 + 6 + 7) = 3200 kg
Fertilization in the second plot: 8400 × 6 / (8 + 6 + 7) = 2400KG
Fertilization in the third plot: 8400 × 7 / (8 + 6 + 7) = 2800 kg

The bottom length of a triangular paddy field is 60 meters, which is 1.6 times the height. What is the area of this paddy field?

Height 60 △ 1.6 = 37.5
The area is 60 × 37.5 △ 2 = 1125 square meters