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On a map with a scale of 1:4000, the central square is 5cm long and 3.75cm wide. On another map with a scale of 1:5000, the center square is wide What is the area of the field on the graph The proportional solution is the equation solution
5 × 4000 △ 5000 = 4cm
3.75 × 4000 △ 5000 = 3cm
The area is 4 × 3 = 12 square centimeters
1/4000:1/5000=5:4
Let the length be x cm and the width y cm
5:4=5：x 5:4=3.75：y
X = 4cm, y = 3cm
The area is 4 × 3 = 12 square centimeters
The distance between AB and ab measured on a 1:20000 scale map is 5cm. If it is measured on a 1:5000 scale map, the distance between AB and ab is 5cm, A. B what is the distance on the map between the two places?
Scale = distance on map: actual distance
1: 20000 = 5cm: actual distance
Actual distance = 5cm × 20000
1: 5000 = x: actual distance
5000x = actual distance = 5cm × 20000
x=5cm×20000/5000=20cm
On a map with a scale of 1:2000000, the expressway distance between cities a and B is measured to be 5.5cm, and the other scale is 1:5000 What's the distance on the map of this road?
1: 2000000 1cm on the map = actual 20km 20 * 5.5 = 110km 1:5000 1cm on the map = actual 50m = 0.05km
110/0.05=2200cm=22m
If a rectangular industrial park with a length of 5cm and a width of 2cm is planned on the map with a scale of 1:n, the actual area of the park is (unit: cm2) () A. n one thousand B. n2 one thousand C. 10n D. 10n2
The actual area of the park is xcm2,
∵ the area of the rectangular industrial park with the length of 5cm and the width of 2cm on the map is 5 × 2 = 10 (cm2),
According to the meaning of the title: 10
x＝(1
n)2，
∴x=10n2，
The actual area of the park is 10n2cm2
Therefore, D
On the other side of the square, it's 75cm wide at the center. It's on a scale of 75cm to 1 What is the area on the map of the central square?
(5 * 4000 / 5000) * (3.75 * 4000 / 5000) = 4 * 3 = 12 square centimeter
Xiaoming's family has a triangular vegetable field. The length of the two sides is 40 meters and 50 meters, and the height of the third side is 30 meters. Calculate the area of the land Is it divided into two cases? One is an obtuse triangle, the other is an acute triangle?
yes
1. S = [(50 ^ - 30 ^ 2) + (40 ^ 2-30 ^ 2)] * 30 * 0.5 = 150 pieces 7 + 600
2: S = (40-10 number 7) * 15 = 600-150 number 7
Xiaoqiang's family has a triangular vegetable field. The length of the two sides is and the height of the third side is. Please help Xiao Qiang calculate the area of this vegetable field (the root of the result is retained). They are 40m and 50m respectively. Sorry for not calling!
Students, as long as you have learned the Pythagorean theorem, this is not a difficult problem. First, according to the known diagram: Gao 30 divides the original triangle into two right triangles, and calculates the unknown sides in the graph according to the Pythagorean theorem. These two unknown sides are the third side of the triangle. The third side is multiplied by the height divided by 2 to get the area of the triangle
Xiaoqiang's family has a triangular vegetable field. The length of the two sides is 40.50, and the height of the third side is 30. Please help Xiaoqiang calculate the area of this field Results the root sign was retained
(√(40²-30²)+(√(50²-30²))*30*0.5
=(10√7+40)*15=150√7+600
Xiaoqiang's family has a triangular vegetable field. The length of both sides is 41m and 15m. The height of the third side is 9m. Please help Xiaoqiang calculate the area of this vegetable field
∵ the length of both sides is 41m and 15m respectively, and the height of the third side is 9m,
The length of the third side is
412-92+
152-92=40+12=52，
The area of this vegetable field is: 1
2 × 52 × 9 = 234 square meters
Pythagorean theorem Xiaoqiang's family has a triangular vegetable field. The length of the two sides is 40cm and 50cm respectively. The height of the third side is 30cm. Calculate the area (root) of this field
The area is (root 70 + 40) times 30 divided by 2
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