![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
In the RT triangle ABC, ∠ C = 90 ° a, B, C denote the opposite sides of ∠ a, ∠ B and ∠ C respectively. Given that a = 6 under the radical sign, ∠ a = 60 ° find B, C
According to the sine theorem, a / Sina = C / sinc = B / SINB, C = √ 6 / (√ 3 / 2) = 2 √ 2, B = √ 2
In RT △ ABC, it is known that ∠ C = 90 ° and the sum of two right angles is 17cm and the area is 30cm? Try to find out the oblique side length of this right triangle
The product of two right angles should be 30
Let a right angle side be r
R*（17－R）/2＝30
R1=12,R2=5
Oblique side length = √ (R1 ^ 2 + R2 ^ 2)
=√(169)
=13(cm)
It is known that △ ABC is an isosceles right triangle with a right angle side length of 1. Take the hypotenuse AC of RT △ ABC as the right angle side, draw the second isosceles RT △ ACD, and then draw the third isosceles RT △ ade The length of the hypotenuse of the nth isosceles right triangle is______ .
According to the Pythagorean theorem, the length of the hypotenuse of the first isosceles right triangle is
The length of the hypotenuse of the second isosceles right triangle is 2=（
2) The length of the hypotenuse of the third isosceles right triangle is 2
2=（
2) The length of the hypotenuse of the nth isosceles right triangle is 3（
2）n．
If the two roots of a quadratic equation of one variable are the two right angles of the RT triangle ABC, and their area is 6, please write a quadratic equation of one variable that meets the requirements
S=1/2ab=6
As long as ab = 12 and a and B are positive numbers
So two are set to 3 and 4,
Equation (x-3) (x-4) = 0,
It's a simple junior high school problem, but it's difficult for senior high school students-（
If the two right angle sides a and B of RT △ ABC are two of the equations x2-3x + 1 = 0, then the circumcircle area of RT △ ABC is______ .
∵ radius of circle r = 1
2c，
According to the fact that two right angle sides a and B are two of the quadratic equation x2-3x + 1 = 0, we can get that
a+b=3，a•b=1，
∴c2=a2+b2=（a+b）2-2a•b=7，
The area of the circumscribed circle of RT △ is π R2 = π ×（
Seven
2）2=7
4π．
So the answer is: 7
4π．
It is known that the two right angles of RT △ ABC are a and B, and a, B are the areas of two circumscribed circles of equation x ^ 2-7x + 12 = 0
Because x ^ 2-7x + 12 = 0
So (x-3) × (x-4) = 0
So the two solutions are 3 and 4
So a 3 and a 4 in a and B
So the radius of circumscribed circle is 2.5,
So the area is 6.25 π
I'm glad to answer it for you, ^ 0^
If the two right angle sides a and B of RT △ ABC are two of the equations x2-3x + 1 = 0, then the circumcircle area of RT △ ABC is______ .
∵ radius of circle r = 1
2c，
According to the fact that two right angle sides a and B are two of the quadratic equation x2-3x + 1 = 0, we can get that
a+b=3，a•b=1，
∴c2=a2+b2=（a+b）2-2a•b=7，
The area of the circumscribed circle of RT △ is π R2 = π ×（
Seven
2）2=7
4π．
So the answer is: 7
4π．
Given that the two right angle sides of the RT triangle ABC are ab = 6cm and AC = 8cm, the side area of the cone is obtained by rotating the straight line where the edge AC is as the axis
The area of the whole cone is 301.5929, the area of bottom circle is 113.0973, and the area of side is 188.4956
In RT △ ABC, ∠ C = 90 ° and right angle sides a and B are two of the equations x? - 3x + 1 = 0 respectively. The area of circumscribed circle of RT △ ABC is calculated Closed today without getting the answer=
∵ a, B are two of X ᙽ 3x + 1 = 0, ? a + B = 3, ab = 1... [the relationship between root and coefficient] ? RT △ the two right angle sides of ABC are a and B ? a ? B ? C ? the Pythagorean theorem, C is an oblique side] ? a ? B + B ? 1 = 0, ? a + B = 3, ab = 1... M RT
In the triangle ABC, if the three angles satisfy 2A = B + C, and the maximum and minimum sides are two of the equation 3x ^ - 27x + 32 = 0, then the area of the circumscribed circle of the triangle is? Would you mind answering another question for me, please,
If 2A = B + Ca + B + C = 180 ° then 3A = 180 ° a = 60 ° can be set as B = 60 + α, C = 60 - α. According to the large angle to the big side and the small angle to the small side in the triangle, so B C is the root of 3x ^ - 27x + 32 = 0
RELATED INFORMATIONS
- 1. It is known that in RT △ ABC ∠ ACB = 90 ° CD ⊥ AB, the perpendicular foot is d BC = 2, BD = radical 3, and the acute angles in △ ABC △ ACDC △ BCD are calculated respectively
- 2. As shown in the figure, in triangle ABC, D is a point on the edge of BC, angle 1 = angle 2, angle 3 = angle 4, angle BAC = 63 ° to find the degree of angle DAC
- 3. It is known that: as shown in the figure, in △ ABC, D is a point on the Ba extension line, AE bisects ∠ DAC, and AE ‖ BC. It is proved that ∠ B = ∠ C
- 4. How to transform polar coordinate form into algebraic form How to convert each other
- 5. How to use the plural in English
- 6. Sin 30 degrees cos square 45 degrees + cos square 30 degrees + sin 60 degrees
- 7. Cosine theorem sine theorem tangent theorem
- 8. What is Tan 30 degrees equal to?
- 9. Tan 45 degrees - cot15 degrees divided by Tan 45 degrees + cot15 degrees =? Please write the formula used)
- 10. Once a, B, C three good friends and took a taxi, told everyone to share the fare, a in the whole journey 1 Get off at 3 and get to 2 3 B also got off the bus, and finally C sat at the end of the line and paid the driver 90 yuan. Please calculate how much fare should be paid to C by a and B?
- 11. In △ ABC, the opposite sides of angles a, B and C are a, B and C respectively, and Tanc = 3 7． (I) find the value of COSC; (II) if CB• CA=5 2, and a + B = 9, find the length of C
- 12. As shown in the figure, in RT △ ABC, ∠ ACB = 90 °, AC = BC, ∠ CAD = ∠ bad, AB = AC + CD
- 13. If there is a point D in the triangle ABC that connects Da, DB and DC, there are () triangles that do not overlap each other
- 14. Both the triangle ABC and the triangle ECD are isosceles right triangles. The angle ACB = angle DCE = 90 ° D is a point on the edge of AB and connected with Ae. When de = 17 and AE = 15, the triangle ABC and ECD are isosceles right triangles, Find the length of ad
- 15. It is known that in △ ABC, ab = AC, CD ⊥ ad is in D, CD = 1 2BC, D is outside △ ABC, and it is proved that ∠ ACD = ∠ B
- 16. It is known that: as shown in the figure, ∠ ACB = 90 ° in △ ABC, CD is high, CE bisects ∠ BCD, and ∠ ACD: ∠ BCD = 1:2, then CE is the center line on AB side, right? Give reasons
- 17. It is known that in isosceles RT △ ABC, ∠ a = 90 ° D is the midpoint of BC, e and F are points on AB and AC respectively, and EA = CF is satisfied. Verification: de = DF
- 18. In the isosceles right triangle ABC, the angle ABC = 90 degrees D is the midpoint on the edge of AC, where de is perpendicular to DF and intersects AB at If AE = 4, FD = 3, find the length of EF
- 19. As shown in the figure, △ ABC, ab = AC, point E is on the extension line of Ca, and ∠ AEF = ∠ AFE. What is the position relationship between the straight line EF and BC? Why?
- 20. As shown in the figure, △ ABC, D is on the extension line of BC, and AC = CD, CE is the middle line of △ ACD, and CF bisects ∠ ACB As shown in the figure, △ ABC, D is on the extension line of BC, and AC = CD, CE is the center line of △ ACD, CF bisects ∠ ACB, intersects AB and F, and proves (1) ce ⊥ CF: (2) CF is parallel to AD