How many degrees centigrade is 20 degrees centigrade

How many degrees centigrade is 20 degrees centigrade

20 ° f = -6.66666666667 ° C
Convert degrees Celsius to Fahrenheit, multiply it by 9, divide by 5, and add 32
From Fahrenheit to centigrade, you just subtract 32, multiply by 5 and divide by 9

What are the values of sin 90 ° cos 90 ° Tan 90 ° cot 90 ° and why?

Sin (π / 2) = 1, cos (π / 2) = 0, Tan (π / 2) = none, cot (π / 2) = 0
According to the trigonometric function image

Sin90 = how much, cos90 = how much, tan90 = how much?

1 0 does not exist

Why does sin90 = 1 cos90 = 0 tan90 not exist,

Tan90 = sin90 / cos90, denominator is not equal to 0, it is meaningless to be equal to 0
So tan90 doesn't exist

What is sin0, sin90 and sin180,

sin0°=0
sin90°=1
sin180°=0

How many are sin90, sin0, tan90, tan0? Sorry, I'm forgetful

sin90=1
sin0=0
Tan90 is meaningless (tan90 = sin90 / cos90, cos90 = 0, so meaningless)
tan0=0

Tan α = 2, find 2Sin α ^ 2 α + 1

2sinα^2α+1=(2sin^2 α-1)+2=2-cos2α
cos2α=(cos^2 α-sin^2 α)/(sin^2α+cos^2α)= (1-tan^2 α)/(1+tan^2 α)
=(1-4)/(1+4)=-3/5
2sinα^2α+1=(2sin^2 α-1)+2=2-cos2α=2+3/5=13/5

Main process of solving 3tan30 °× cos30 ° + tan45 ° + sin30 ° - sin60 °

Special angle trigonometric function calculation problem:
3tan30°×cos30°+tan45°+sin30°-sin60°
=3x√3/3 x √3/2 +1 + 1/2 -√3/2
=(6-√3)/2

Radix 2sin45 ° + cos30 ° * tan60 ° - the square of Radix (- 3)

2sin45 = radical 2
Cos30 = half root 3 tan50 = root 3 cos30 * tan60 = 1.5
There can't be negative numbers in the root sign. So you understand it as root 3. The square of root 3 = 3
Therefore, the original formula = radical 2-1.5

I would like to ask someone to know the mathematical problem sin30 ° cos30 ° - Tan 45 ° to use ah, thank you very much {random number C

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