What is Tan 5 / 12

What is Tan 5 / 12

twenty-two point six two

Tan5 ° + 1 / tan5 ° - 2 / cos80 ° simplification and evaluation

The first two terms are divided into two parts, and then the formula of double angle is used to transform the former two terms into the one related to 10 degrees
=2/sin10°-2/cos80°=0

How to calculate sin (a + β) cos (R - β) - cos (β + a) sin (β - R) and tan5 π / 4 + tan5 π / 12 / 1-tan5 π / 12

sin(a+β)cos(r-β)-cos(β+a)sin(β-r)=sin(a+β)cos(r-β)-cos(a+β)sin[-(r-β)]=sin(a+β)cos(r-β)+cos(a+β)sin(r-β)=sin[(a+β)+(r-β)]=sin(a+r)[(tan5π/4)+(tan5π/12)]/[1-(tan5π/12)]=[(tan(π+π/4))...

The order of Tan 3, Tan 4, Tan 5 is______ (linked with "<"

By π
2 ＜ 3 ＜ π, tan3 ＜ 0, and π ＜ 4 ＜ 3 π
2, Tan 4 > 0 is obtained from 3 π
2 ＜ 5 ＜ 2 π, Tan 5 ＜ 0,
According to the properties of tangent function, we can get that y = TaNx is in (3 π)
2, 2 π),
If tan3 = Tan (3 + π), then 3 π
When 2 ＜ 5 ＜ 3 + π ＜ 2 π, tan5 ＜ Tan (3 + π) = tan3 can be obtained,
So the answer is: Tan 5 < Tan 3 < Tan 4

（tan5°-cot5°）×cos70° 1+sin70°=______ .

(tan5 ° - cot5 °) × cos70 ° 1 + sin70 ° = (sin5 ° cos5 ° - cos5 ° sin5 °) · sin20 ° 1 + cos20 ° = sin25 ° - cos25 ° sin5 ° cos5 ° · sin20 ° 1 + cos20 ° = - cos10 ° 12sin10 ° · 2sin10 ° cos10 ° 2cos210 ° = - 2

(tan5 degree - 1 / tan5 degree) * cos70 degree / (1 + sin70 degree)

The original formula = (sin5 ° / cos5 ° - cos5 ° - sin5 °) sin20 ° / (1 + cos20 °)
=-(2cos10°/sin10°)sin20°/(2cos²10°)
=-4(cos²10°sin10°)/(2cos²10°sin10°)
=-2.

Evaluation (tan5-cot2) * cos70 / (1 + sin70) process

(Tan 5 degrees - cot5 degrees) * cos 70 degrees / (1 + sin 70 degrees)
Molecular = (Tan 5 degrees - cot5 degrees) * cos 70 degrees
=(（sin5/cos5)-(cos5/sin5))*cos70
=((sin²5-cos²5)/(sin5cos5))*cos70
=(-2cos10/sin10)*sin20
=(-2cos10/sin10)*(2sin10cos10)
=-4cos²10
=-2(1+cos20)
Denominator = 1 + cos20
Numerator divided by denominator = - 2

（tan5°-cot5°）×cos70° 1+sin70°=______ .

（tan5°-cot5°）×cos70°
1+sin70°=（sin5°
cos5°-cos5°
sin5°）•sin20°
1+cos20°
=sin25°−cos25°
sin5°cos5°•sin20°
1+cos20°=−cos10°
One
2sin10°•2sin10°cos10°
2cos210°=-2，
So the answer is: - 2

Find the value of (tan5 ° - 1 / tan5 °) * cos70 ° / (1 + sin70 °)

First simplify the numerator = ((sin5 / cos5) - (cos5 / sin5)) * cos70 = ((sin5-cos5) / (sin5cos5)) * cos70 = (- 2cos10 / sin10) * (sin10 / sin10) * (2sin10 / sin10) = - 4cos10 = - 2 (1 + cos20) the denominator is reduced to 1 + cos20 divided by the denominator to get - 2. Do you understand?

Evaluation: 1 + cos20 degree 2sin20°−sin10°(1 tan5°−tan5°)．

Original formula = 2cos210 degree
4sin10°cos10°−sin10° (cos5°
sin5°−sin5°
cos5°)=2cos210°
4sin10° cos10°− 2sin10° (cos25° −sin25°
2sin5°cos5°)
=cos10°
2sin10°−2cos10° ＝cos10° −2sin20°
2sin10°
=cos10°−2sin(30°−10°)
2sin10°＝cos10°−2sin30°cos10° +2cos30° sin10°
2sin10°
=cos30° ＝
Three
Two