Measure the length of the railway. The propagation speed of sound in air and steel is 340m / s and 5000m / s. one person knocks and one person hears it twice, with an interval of 2S. Calculate the length of the railway

Measure the length of the railway. The propagation speed of sound in air and steel is 340m / s and 5000m / s. one person knocks and one person hears it twice, with an interval of 2S. Calculate the length of the railway

Set length of railway x M
According to the meaning of the question, you can get
x/340 - x/5000 = 2
5000x-340x=3400000
Solution equation
x = 729.614
The railway is 729.614m long

Suppose that the speed of sound propagation in the air is 340m / s and that in steel is 1500m / s. one person knocks one end of the iron bridge with a hammer and the other person hears two sounds at the other end with a difference of 0.5 seconds, then the length of the iron bridge is about______ m．

Let the length of the bridge be s,
∵v=s
t，
The propagation time of sound in the air:
T air = s
V air = s
340m/s   ①，
T iron bridge = s
V steel = s
1500m/s   ②，
Known t air-t steel = 0.5s   ③，
According to the solution of ①, ② and ③: s ≈ 219.8m;
So the answer is: 219.8

Suppose that the speed of sound propagation in the air is 340m / s and that in steel is 1500m / s. one person knocks one end of the iron bridge with a hammer and the other person hears two sounds at the other end with a difference of 0.5 seconds, then the length of the iron bridge is about______ m．

Let the length of the bridge be s,
∵v=s
t，
The propagation time of sound in the air:
T air = s
V air = s
340m/s   ①，
T iron bridge = s
V steel = s
1500m/s   ②，
Known t air-t steel = 0.5s   ③，
According to the solution of ①, ② and ③: s ≈ 219.8m;
So the answer is: 219.8

The speed of sound in the air is 340m / s, in the steel is 5000m / s, knock one end of the iron bridge with a hammer, and hear two sounds at the other end with an interval of 3S. What is the length of the iron bridge?

If the bridge length is s, the speed of sound in air is V1, and the speed in steel is V2, then:
S=V1t 1
S=V2(t+3) 2
From equation 1, t = s / V1 is substituted into equation 2 to obtain:
S=V2(S/V1+3)
It is solved that s = 3v1v2 / (v2-v1) = 3x340x5000 / (5000-340) = 5100000 / 4660 = 1094.42
The length of the iron bridge is 1094.42 meters

A 100 meter iron pipe filled with water is knocked at one end and heard at the other end. It is known that the sound travels 5000 meters per second in steel, It travels 1500 meters per second in the water. How many times can you hear the sound at the other end? The interval between two sounds must be more than 0.1s!

3 times, iron, water, air
Maybe the interval is too short. It's mixed once every three times

The speed of sound in the air is 340 meters per second and 5000 meters per second in steel. Someone hits one end of the iron bridge with a hammer and hears two sounds at the other end of the bridge three seconds apart The answer is 1094 meters [process], so we can know the length of the iron bridge?

T1-T2 = t, T1 = s / V1, T2 = s / v2
s/v1-s/v2=t
Substituted data: S / 340m / S-S / 5000m / S = 3S
Solution: S = 1094.4m
A: the length of the iron bridge is 1094.4 meters