[(log4) ^ 3 + (log8) ^ 3] [(log3) ^ 2 + (log9) ^ 2] = how many

[(log4) ^ 3 + (log8) ^ 3] [(log3) ^ 2 + (log9) ^ 2] = how many

(log12)^5

What is the result of simplifying log3 (4) * log4 (5) * log5 (8) * log8 (9)?

=(lg4/lg3)(lg5/lg4)(lg8/lg5)(lg9/lg8)
=2

Simplification (log4 (3) + log8 (3)) (log3 (2) + log9 (2))

(log4(3)+log8(3))(log3(2)+log9(2))
=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)
=5lg3/6lg2X3lg2/2lg3
=5/6X3/2
=5/4

Help to simplify the following: logac * logca. Log2 3 * log3 4 * log4 5 * log5 2

1、logaC × logcA= logaC × (1/logaC)=1
2、log2 3 × log3 4 × log4 5 × log5 2
=[1/(log3 2)] × 2log3 2 × [1/(log5 4)] × log5 2
=2 × [1/2(log5 2)] × log5 2
=2 × (1/2)
=1

Log2 true number 3 * log3 true number 4 * log4 true number 5 * log5 true number 2 how to simplify by using the bottom changing formula

It can be changed into: Lg3 / LG2 * (2lg2 / Lg3) * (lg5 / 2lg2) * (LG2 / lg5)
The result is: 1

Log2 3 · log3 4 · log4 5 · log5 2 is preceded by the base number

log2 3 · log3 4 ·log4 5 ·log5 2
=lg3/lg2 * lg4/lg3 * lg5/lg4 * lg2/lg5
=1