Does the dog pull the sled in a uniform circular motion with constant acceleration?

Does the dog pull the sled in a uniform circular motion with constant acceleration?

When a dog pulls a sleigh in a uniform circular motion, the acceleration remains the same. That's right. Use the formula a = V ^ 2 / R, V remains the same, R remains the same, so a remains the same

The acceleration of an object in uniform circular motion must be () A. Proportional to the square of its angular velocity B. Directly proportional to the square of its linear velocity C. Inversely proportional to the radius of its motion D. It is proportional to the product of linear velocity and angular velocity of its motion

A. By a = R ω 2=v2
R shows that when the radius is constant, the acceleration is directly proportional to the square of the angular velocity and the square of the linear velocity; If the angular velocity is constant, it is proportional to the radius; If the linear velocity is constant, it is inversely proportional to the radius; Therefore, ABC has no control variable and ABC is wrong;
D. By a = v ω It can be seen that the acceleration must be directly proportional to the product of angular velocity and linear velocity of motion; Therefore, D is correct;
Therefore: D

Why does the linear velocity of an object in uniform circular motion remain the same since it has acceleration?

In fact, uniform circular motion is also a variable speed motion, but it changes the direction of speed. Speed is a vector, so changing speed means changing one of size and direction, and then the speed changes

The acceleration of uniform circular motion becomes constant

Change. Although the size has not changed, the direction has been changing. The centripetal acceleration a = V ^ 2 / R, when v = 0, a = 0, but it is stationary at this time; When the radius R is infinity, a tends to 0, but it moves in a straight line. In uniform circular motion, a is not 0

Who can explain why the velocity in the acceleration direction of uniform circular motion is always zero If you say that the direction of resultant force is perpendicular to the direction of motion, so... Thank you. Please look at what I ask

The reason why the horizontal acceleration is equal to zero is explained on the first floor. The reason why the velocity in the acceleration direction is equal to zero is that the motion direction of the object is inconsistent with the direction of the force, and the speed meets the centripetal force F = MV2 / R for the object to make a uniform circular motion. The object can not get rid of the force, but the speed is not enough to break away from the centripetal force, so make a uniform circular motion

How to express the acceleration of uniform circular motion Uniform circular motion means that the speed is constant, so it is a change of direction. In this case, how to express the acceleration?

a=v^/r=w^2*r=4π^2*r/T^2
v: Linear velocity
w: Angular velocity
^: Square
*: multiplication sign
/: division sign (fractional line)