If the coordinates of the three vertices of a triangle are a (- - 5,2), B (1,2), C (3, - 10), then the area of triangle ABC

If the coordinates of the three vertices of a triangle are a (- - 5,2), B (1,2), C (3, - 10), then the area of triangle ABC

With ab as the bottom edge, the bottom edge is 6 long, 12 high, and area: 6 * 12 * 0.5 = 36

The coordinates of the three vertices a, B and C of triangle ABC are a (2, - 1), B (1, - 3) and C (4, - 3.5) respectively. Find the area of this triangle ※ please write down the process,,, →^^←

Draw a drawing and construct a rectangle. Subtract the area of three right triangles from the rectangular area (calculate the side length and area according to the coordinates). The area is 6-3 / 2-1 / 2-2 = 2

As shown in the figure, the three vertex coordinates of triangle ABC are a (- 2,3), B (- 4, - 1) and C (2,0) to calculate the area of triangle ABC

The equation of a (- 2,3), B (- 4, - 1) straight line AB is y = 2x + 7 when y = 0, x = - 7 / 2
Area of triangle ABC = (2 + 7 / 2) x (3 + 1) = (11 / 2) X4 = 22

As shown in the figure, the vertex coordinates of triangle ABC are a (2, - 1), B (4,3) C (1,2) respectively. Find the area of ABC

BC length is (4-1) ^ 2 + (3-2) ^ 2 = root 10 (this is the distance formula between two points)
Then find the linear analytical formula of BC
Let LBC: y = KX + B
Substitute the coordinates of B and C into the equation
2=k+b,3=4k+b
Find k = one-third, B = five-thirds
So LBC: y = 1 / 3x + 5 / 3
That is, x-3y + 5 = 0
Then find the distance from a to BC
The distance formula from the applied point to the straight line is
Absolute value of distance d = 2 + (- 3) * - 1) + 5 / 1 ^ 2 + 3 ^ 2 = root 10
So area = 0.5 * BC * d = 5

In the right angle triangular coordinate system as shown in figure 12.1-4, the area of the triangle is calculated from the coordinates a (- 1,3) B (- 2, - 1) C (2,0) of each vertex of triangle ABC The best answer is today

As shown in the figure, divide the triangle into two parts
The upper half of the Y axis is a part and the lower half is a part
Make vertical lines from two points a and B to the X axis to obtain two high lines with lengths of 3 and 1 respectively
The line AB equation 4x-y + 7 = 0 is obtained from the two-point coordinates of AB, and the intersection D (- 7 / 4,0) of AB line and X axis is obtained by making y = 0
Therefore, the length of DC is 15 / 4
S=(15/4*3)/2+(15/4*1)/2
=15/2

In the rectangular coordinate system as shown in the figure, the coordinates of the vertices of triangle ABC are a (- 1,3), B (- 2, - 1), C (2,0), and calculate the area of triangle ABC

eight
4*(1+3)/2=8