An organic substance A is composed of C, h and O. under certain conditions, the transformation relationship between a, B, C, D and E is as follows: It is known that the vapor density of C is 22 times that of hydrogen under the same conditions, and silver mirror reaction can occur (1) The name of the functional group contained in substance D is __, The structural formula of substance e is ___, (2) Write the chemical equation to achieve the following conversion: ①A→B______, ②A+O 2 →C______ ③ C equation for reaction with silver ammonia solution ___

An organic substance A is composed of C, h and O. under certain conditions, the transformation relationship between a, B, C, D and E is as follows: It is known that the vapor density of C is 22 times that of hydrogen under the same conditions, and silver mirror reaction can occur (1) The name of the functional group contained in substance D is __, The structural formula of substance e is ___, (2) Write the chemical equation to achieve the following conversion: ①A→B______, ②A+O 2 →C______ ③ C equation for reaction with silver ammonia solution ___

(I) since sin (C-A) = 1, C − a =
π
two
, and C + a = π - B,
∴A=
π
four

B
two

∴sinA=sin(
π
four

B
two
)=
two
two
(cos
B
two
−sin
B
two
),
∴sin2A=
one
two
(1−sinB)=
one
three

And Sina > 0, ‡ Sina =
three
three
(II) as shown in the figure, it is obtained from the sine theorem
AC
sinB

BC
sinA
∴BC=
ACsinA
sinB

six

three
three
one
three
=3
two

Sinc = sin (a + b) = sinacosb + cosasinb=
three
three
×
two
two
three
+
six
three
×
one
three

six
three
∴S△ABC=
one
two
AC•BC•sinC=
one
two
×
six
× three
two
×
six
three
=3
two

An organic substance A is composed of C, h and O. under certain conditions, the transformation relationship between a, B, C, D and E is as follows: It is known that the vapor density of C is 22 times that of hydrogen under the same conditions, and silver mirror reaction can occur (1) The name of the functional group contained in substance D is __, The structural formula of substance e is ___, (2) Write the chemical equation to achieve the following conversion: ①A→B______, ②A+O 2 →C______ ③ C equation for reaction with silver ammonia solution ___

(I) since sin (C-A) = 1, C − a =
π
two
, and C + a = π - B,
∴A=
π
four

B
two

∴sinA=sin(
π
four

B
two
)=
two
two
(cos
B
two
−sin
B
two
),
∴sin2A=
one
two
(1−sinB)=
one
three

And Sina > 0, ‡ Sina =
three
three
(II) as shown in the figure, it is obtained from the sine theorem
AC
sinB

BC
sinA
∴BC=
ACsinA
sinB

six

three
three
one
three
=3
two

Sinc = sin (a + b) = sinacosb + cosasinb=
three
three
×
two
two
three
+
six
three
×
one
three

six
three
∴S△ABC=
one
two
AC•BC•sinC=
one
two
×
six
× three
two
×
six
three
=3
two

An organic substance A is composed of C, h and O. under certain conditions, the transformation relationship between a, B, C, D and E is as follows: It is known that the vapor density of C is 22 times that of hydrogen under the same conditions, and silver mirror reaction can occur (1) The name of the functional group contained in substance D is __, The structural formula of substance e is ___, (2) Write the chemical equation to achieve the following conversion: ①A→B______, ②A+O 2 →C______ ③ C equation for reaction with silver ammonia solution ___

(I) because sin (C-A) = 1, C − a = π 2, and C + a = π - B, ‡ a = π 4 − B2, ‡ Sina = sin (π 4 − B2) = 22 (cosb2 − sinb2), ‡ sin2a = 12 (1 − SINB) = 13, and Sina > 0, ‡ Sina = 33 (II) as shown in the figure, acsinb = bcsina ‡ BC = a

If ABC area of obtuse triangle is 1 / 2, ab = 1, BC = root 2, then what is AC

1/2=(1/2)AB*BC*sinB
I.e. 1 / 2 = (1 / 2) 1 * √ 2 * SINB
SINB = √ 2 / 2
So B = 45 or B = 135
When B = 45
AC ²= AB ²+ BC ²- 2AB*BC*cosB
=1+2-2√2*√2/2
=1
The triangle is a right triangle
So B = 135
Then AC ²= AB ²+ BC ²- 2AB*BC*cosB
=1+2+2√2*√2/2
=5
Get AC = √ 5

a. B and C are the three sides of triangle ABC, whose area is 12, radical 3, BC = 48, B-C = 2. Find a

From the triangular area formula s = (1 / 2) bcsina, then 12 √ 3 = (1 / 2) 48sina, that is, Sina = √ 3 / 2, from the triangular area formula s = (1 / 2) bcsina, then 12 √ 3 = (1 / 2) 48sina, that is, Sina = √ 3 / 2A = 60 ° or 120 °, BC = 48, B-C = 2, B = 8, C = 6, when a = 60 °, from the cosine theorem a = √ B ²+ c ²- 2bcc...

In the known triangle ABC, ab = root 3, AC = 1, and the area of triangle ABC = root 3 / 4. What is the length of BC?

Area of triangle = 0.5 * AB * ac * Sina
sinA=1/4
Cosa can be obtained
Then BC can be obtained by cosine theorem