: if the area of triangle ABC is s and the three sides are a, B and C, what is the radius of the inscribed circle of the triangle?, : fill in the blanks, : it's probably expressed by a, B, C and s,

: if the area of triangle ABC is s and the three sides are a, B and C, what is the radius of the inscribed circle of the triangle?, : fill in the blanks, : it's probably expressed by a, B, C and s,

Let the radius be r,
ar/2+br/2+cr/2=s,
(a+b+c)r/2=s,
r=2s/(a+b+c)

If the area of △ ABC is s and the lengths of the three sides are a, B and C respectively, what is the radius of the inscribed circle of the triangle? Just fill in the blanks thank you.

1/2*a*r + 1/2*b*r + 1/2*c*r = S
r= 2S/(a+b+c)

If the area of triangle ABC is s, and the lengths of three sides are a, B and C respectively, what is the radius of the inscribed circle of the triangle (the process to solve the problem)

Connect the center of the circle with each vertex to form three triangles. From the radius of the tangent perpendicular to the tangent point, the ABC area of the triangle s = 1 / 2 (Ar + br + CR) (R is the radius of the inscribed circle), then r = 2S / (a + B + C)

Let a, B and C be the opposite side lengths of ∠ A and ∠ B in triangle ABC respectively, the area of triangle ABC is s, and R is the radius of its inscribed circle 1. Verify that r = s divided by P, where p = 2% (a + B + C) If the triangle ABC is a right triangle and the angle c = 90 degrees, verify that r = 2 / 2 (a + B-C)

Make a triangle casually, and make the radius from the center of the inscribed circle to each edge, and then connect the center and the vertices of the triangle
Get three triangular rows and their respective high figures,
It can be proved by listing the equation according to the area formula
R = s divided by P, where p = 2 / 2 (a + B + C)
2. If triangle ABC is a right triangle, angle c = 90 degrees,
Make a graph, and make the radius from the center of the inscribed circle to each edge, and then connect the center of the circle and the vertices of the triangle,
You will find that the six triangles divided by these lines are three pairs of congruent triangles, which are divided into a pair by each angle,
And the corner of the right angle has a square
C = B-R + (A-R) can be listed according to the equality of the sides of the de equal triangle
R = 2 / 2 (a + B-C)
 
 

The car moves in a straight line at a constant speed of 20 meters per second, and the acceleration after braking is 5 meters per second. Then the ratio of the displacement of the car in the first three seconds after braking to that in the next second is

5 to 1

In △ ABC, a, B and C are the opposite sides of ∠ a, ∠ B and ∠ C respectively. If a, B and C form an equal difference sequence, ∠ B = 30 °, the area of △ ABC is 3 2, then B equals () A. 1+ three two B. 1+ three C. 2+ three two D. 2+ three

∵ a, B and C form an equal difference sequence, ∵ 2B = a + C, get A2 + C2 = 4b2-2ac, and ∵ ABC has an area of 32, ∠ B = 30 °, so from s △ ABC = 12acsinb = 12acsin30 ° = 14ac = 32, get AC = 6. ∵ A2 + C2 = 4b2-12. From the cosine theorem, get CoSb = A2 + C2 − b22ac = 4B2 − 12 − B22 × 6＝b...