It is known that the edge length of regular tetrahedron a-bcd is a (four faces are congruent regular triangles), e and F are the midpoint of edges BC and ad respectively. Find the angle formed by EF and ab

It is known that the edge length of regular tetrahedron a-bcd is a (four faces are congruent regular triangles), e and F are the midpoint of edges BC and ad respectively. Find the angle formed by EF and ab

Take the midpoint of AC as M. use the assignment method to make the edge length of a-bcd 2. ∵ ACD is an equilateral triangle, AF = DF = 1, ∵ CF ⊥ DF, ∵ CF = √ 3DF = √ 3. ∵ abd is an equilateral triangle, AF = DF = 1, ∵ BF ⊥ DF, ∵ BF = √ 3DF = √ 3. ∵ BF = CF = √ 3, be = CE = 1, ∵ EF ⊥ BC, ∵ EF = √ (BF ^

As shown in the figure, points e, F, G and H are the midpoint of edges AB, BC, CD and Da of parallelogram ABCD respectively Verification: △ bef ≌ △ DGH

It is proved that ∵ quadrilateral ABCD is a parallelogram,
∴∠B=∠D,AB=CD,BC=AD.
And ∵ e, F, G and H are the midpoint of the four sides of the parallelogram ABCD respectively,
∴BE=DG,BF=DH.
∴△BEF≌△DGH.

As shown in the figure, points e, F, G and H are the midpoint of edges AB, BC, CD and Da of parallelogram ABCD respectively Verification: △ bef ≌ △ DGH

It is proved that ∵ quadrilateral ABCD is a parallelogram,
∴∠B=∠D,AB=CD,BC=AD.
And ∵ e, F, G and H are the midpoint of the four sides of the parallelogram ABCD respectively,
∴BE=DG,BF=DH.
∴△BEF≌△DGH.

Given the arc length and radius of the circle, the formula for calculating the center angle of the circle fast

Circumference of circle = 2 π R
An arc is part of a circle, so
Arc length = circumference of the circle * (center angle of the arc / 360 °)
=2 π R * center angle / 360 °
Because 2 π = 360 °
therefore
Sector center angle = arc length / radius
The unit obtained is radians, which should be replaced by angular degrees

The arc length formulas under angle system and radian system are used to calculate the length of the arc corresponding to the center angle of 60 degrees in a circle with a radius of 1m

Angle system: l = (center angle of Arc / 360 °) * circumference
=(60°/360°)*2π
=π/3
Radian system: l = (radian to the center angle of the circle / (2 π)) * circumference
=((π/3)/(2π))*2π=π/3

(Lesson 11 8) calculate the length of the arc corresponding to the center angle of 60 degrees in a circle with a radius of 1m by using the arc length formula under the angle system and the solitude system respectively

Using the arc length formulas under the angle system and the solitude system respectively, calculate the length C of the arc corresponding to the center angle of a = 60 degrees in the circle with radius r = 1m?
C=(2*PI*R)*A/360=(2*PI*1)*60/360=PI/3m
A = 60 degrees = 60 * pi / 180 = pi / 3 radians
C=R*A=1*PI/3=PI/3m