As shown in the figure, points e, F, G and H are the midpoint of edges AB, BC, CD and Da of parallelogram ABCD respectively Verification: △ bef ≌ △ DGH

As shown in the figure, points e, F, G and H are the midpoint of edges AB, BC, CD and Da of parallelogram ABCD respectively Verification: △ bef ≌ △ DGH

It is proved that ∵ quadrilateral ABCD is a parallelogram,
∴∠B=∠D,AB=CD,BC=AD.
And ∵ e, F, G and H are the midpoint of the four sides of the parallelogram ABCD respectively,
∴BE=DG,BF=DH.
∴△BEF≌△DGH.

As shown in the figure, points e, F, G and H are the midpoint of edges AB, BC, CD and Da of parallelogram ABCD respectively Verification: △ bef ≌ △ DGH

It is proved that ∵ quadrilateral ABCD is a parallelogram,
∴∠B=∠D,AB=CD,BC=AD.
And ∵ e, F, G and H are the midpoint of the four sides of the parallelogram ABCD respectively,
∴BE=DG,BF=DH.
∴△BEF≌△DGH.

It is known that in Zai trapezoidal ABCD, CD ‖ AB, ∠ a = 40 °, ∠ B = 70 °, test description ad = ab-dc

Proof: make CE ‖ AD and hand over AB to point E
Then the quadrilateral adce is a parallelogram
∴AD=CE,∠BEC=∠A=40°,AE=CD
∵∠B=70°
∴∠BCE=70°
∴CE=BE
∵BE=AB-AE=AB-CD
∴AD=AB-CD

It is known, as shown in the figure, in the trapezoidal ABCD, AB / / CD, ∠ a = 60 °, ∠ B = 45 °, DC = 2, ad = 4, calculate the area of the trapezoidal ABCD

As high De, CF in △ DAE, ∠ a = 60, ad = 4 ‡ AE = 2, de = 2, root number 3 = CF
In △ CFB, ∠ B = 45 ° BF = CF = 2 root numbers 3 ‡ AB = 4 + 2 root numbers 3
‡ s trapezoidal ABCD = 2 root numbers 3 * (2 + 4 + 2 root numbers 3) / 2 = 6 root numbers 3 + 6

Why is a matrix reversible, its row vector group is linearly independent, and its column vector group is also linearly independent?

Because if a is reversible, ax = 0 has a unique solution 0, and XA = 0 also has a unique solution 0, which is exactly the definition of linear independence between column vector group and row vector group

Let a and B be n * M-type and m * n-type matrices respectively, and C = AB be a reversible matrix. It is proved that the column vector group of B is linearly independent Specifically,

It is proved that R (c) = n is known reversibly by C
So n = R (c) = R (AB)