If the arc number of the center angle of the sector is 2 and the chord length of the sector arc is 2, the area of the sector is () A. 1 sin21 B. 2 sin22 C. 1 cos21 D. 2 cos22

If the arc number of the center angle of the sector is 2 and the chord length of the sector arc is 2, the area of the sector is () A. 1 sin21 B. 2 sin22 C. 1 cos21 D. 2 cos22

The radius of the sector is: 1
sin1．
From the sector area formula, the area of the sector is: 1
two × two × one
sin21=1
sin21
So choose a

The chord length of the center angle of 1 radian is 2. Find the arc length of the center angle and the area of the sector and bow sandwiched by the center angle

Draw a graph, let the chord AB = 2, and the center angle it faces is ∠ AOB. Make OD ⊥ AB in D (o is the center of the circle)
At RT Δ In oad, ad = rsin1 / 2 ∠ AOD, i.e. 1 = rsin1 / 2
∴r＝1/sin1/2
Arc length L = α r＝1*1/(sin1/2）=1/（sin1/2）
The other two quantities can replace the formula. (according to α＝ LR, l = R)

If the arc number of the center angle of the sector is 2 and the chord length of the sector arc is 2, the area of the sector is () A. 1 sin21 B. 2 sin22 C. 1 cos21 D. 2 cos22

The radius of the sector is: 1
sin1．
From the sector area formula, the area of the sector is: 1
two × two × one
sin21=1
sin21
So choose a

Given that the chord length of the center angle with radian number 2 is also 2, the arc length of the center angle is () A. 2 B. 2sin1 C. 2sin-11 D. sin2

As shown in the figure, in the sector OAB, the center angle ∠ AOB = 2, and the point passing through 0 is OC ⊥ AB at point C,
Extend OC, intersect arc AB at point D,
Then ∠ AOD = ∠ BOD = 1, AC = 1
2AB=1，
∵ in RT △ AOC, Ao = AC
sin∠AOC=1
Sin1, radius r = 1
sin1，
‡ arc AB length L= α• r=2•1
sin1=2
sin1=2sin-11．
Therefore: C

What are the calculation formulas of arc length and sector area?

Please accept

Application of arc length formula and sector area 1. The radius of the circle is 240mm. Find the degree of the center angle of the circle opposite to the arc with a length of 500mm on the circle 2. The wheel with a diameter of 20cm rotates at the speed of 45rad \ S. calculate the arc length of a point on the wheel circumference after 5S 3. The circumference of the navigation compass is divided into 32 equal parts, and the center angle of each equal part is expressed in degrees and radians respectively 4. The diameter of the flywheel of the steam engine is 1.2m. Rotate counterclockwise at the speed of 300r / min to find 1. The number of radians the flywheel rotates every 1s. 2. The arc length of a point on the wheel circumference rotates every 1s 5. Cut a sector plate on the circular metal plate with radius OA = 100cm, make the length of arc AB 112cm, and find the center angle ∠ AOB (accurate to 1 degree) 6. Given that the length of the arc opposite to the center angle of 1 ° is 1m, what is the radius of the circle? 7. It is known that the arc with a length of 50cm is 200 °, and find the radius of the circle where the arc is located (accurate to 1cm) I know a lot of problems, just need to solve the problem in detail, OK~ I hope you math experts can help! esteem it a favor. Correct answer 1. About 119 ° 2.2250cm 3.11 ° 15 min, 6 / π 4. (1) 10 π, (2) 6 π M. 5.64 ° 6. About 57.3m 7.14cm I don't have a process.. I need the problem-solving process of experts. The more detailed the appointment. Involving the arc length system of senior one mathematics,

[all solutions are in radian system] 1. R θ= l 240mm=500mm* θ θ= 25/12rad 2. v= ω R l=vt l= ω Rt=45rad/s*0.2m*5s=45m 3. θ= 2π/32=π/16rad=11.25° 4. 300r/min=5r/s=10πrad/s (1) θ=ω t=10π*1s=10πrad(2)l= ω Rt=10πrad/s*1....