In a circle with radius 1, the length is equal to What is the central angle of the string of 2______ Degrees

In a circle with radius 1, the length is equal to What is the central angle of the string of 2______ Degrees

As shown in the figure, in ⊙ o, ab=
2，OA=OB=1，
∴AB2=OA2+OB2，
‡△ AOB is a right triangle, and ∠ AOB = 90 °,
That is, the length is equal to
The central angle of the chord of 2 is 90 °
So the answer is: 90

Is the length of a string equal to the radius and the central angle of the circle opposite the string equal to 1 radian? Why?

Not equal to
The chord and the radius at both ends form an equilateral triangle with a center angle of 60 degrees and π / 3 radians

A chord with a length equal to the radius has a central angle equal to______ Radians

Because a string with a length equal to the radius has a center angle of π
3 radians
So the answer is: π
3．

If the length of a string is equal to the radius, the number of radians of the center angle of the string is? Why?

60°
The chord is equal to the radius. Isn't the triangle composed of the chord and two radii an equilateral triangle? It's 60 degrees, of course

If the length of an arc is equal to the side length of the inscribed regular triangle of its circle, the arc length of its center angle is a. π / 3 B.2 π / 3 C. radical 3 D.2 I understand the solution equal to root three. What I want to ask is why it is not 2 π / 3, because if you draw a picture, the center angle of the arc length is obviously 120 °, but why not

The side length of an inscribed regular triangle is the chord length, not the arc length
If the center angle of the arc length is 120 °, then the arc length must be greater than the side length of the inscribed regular triangle of the circle
Therefore, when the arc length is equal to the side length of the inscribed regular triangle of its circle, the center angle of the arc length must be less than 120 °

If the length of an arc is equal to the side length of the inscribed regular triangle of its circle, the number of radians of its center angle is () A. three B. 2 three C. π three D. 2π three

Let the radius of the circumscribed circle of the equilateral △ ABC be 2, take the midpoint D of BC and connect od and OC, then ∠ OCB = 30 °
According to the inference of the vertical diameter theorem, OD ⊥ BC,
Od = 1 in RT △ OCD
2OC=1，∴CD=
3. Side length BC = 2
3．
Let the number of radians of the center angle of the arc be θ，
Then 2 can be obtained from the arc length formula θ= two
3，∴ θ=
3．
Therefore: a