If a string divides a circle into two arcs of 1:3, the circumferential angle of the string is

If a string divides a circle into two arcs of 1:3, the circumferential angle of the string is

A string divides the circle into two arcs of 1:3,
Then the circumferential angle of this chord is 135 ° or 45 °

In circle O, the chord center distance of string AB is equal to half of the chord length, and the arc length of the string is 47 π cm. Find the radius of circle o There should be a problem-solving process, thank you

Center angle a = 45 * 2 = 90 degrees
Arc length = 2 * pi * r * 90 / 360 = 47 * pi
2*PI*R/4=47*PI
R/2=47
R=94cm

In ⊙ o with radius 1, chord AB = 1, then The length of AB is () A. π six B. π four C. π three D. π two

As shown in the figure, make OC ⊥ ab,
Then the vertical diameter theorem shows that BC = 1
two
∵ chord AB = 1,
∴sin∠COB=1
two
∴∠COB=30°
∴∠AOB=60°
∴
Length of AB = 60 π
180=π
3．
Therefore, C

In circle O with radius 2, chord AB is equal to 2 root signs. 3. Find the length of arc AB?

4pai / 3

In ⊙ o with radius 1, chord AB = 1, then The length of AB is () A. π six B. π four C. π three D. π two

As shown in the figure, make OC ⊥ ab,
Then the vertical diameter theorem shows that BC = 1
two
∵ chord AB = 1,
∴sin∠COB=1
two
∴∠COB=30°
∴∠AOB=60°
∴
Length of AB = 60 π
180=π
3．
Therefore, C

In a circle with a radius of 2, the center angle of the chord with a length of 2 is

ninety
Pythagorean theorem!