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Arrange 3x to the 3rd power y + xy2nd power - 2y3rd power - 3x2 power according to the descending power of X
3x ³ y-3x ²+ xy ²- 2y ³
1/xy2 × (x to the - 2nd power y) to the - 1st power ÷ (- X / Y2)
Original formula = 1 / XY2 times x to the power of Y, and then multiply (- Y2 / x)
=-1/y
If MX3 + 3nxy2 + 2x3-xy2 + y does not contain the third power, what is the value of 2m-3n? The number after the letter is an index. I don't know how to superscript, so it's written like this
MX3 + 3nxy2 + 2x3-xy2 + y = (m-2) x ^ 3 + (3n-1) XY2 + y excluding the third power
Then m-2 = 0,3n-1 = 0, M = 2, n = 1 / 3
So 2m-3n = 4-1 = 3
3x2 power y · (- 2x3 power y Square)=
3x ² y·(-2x ³ y ²)
=-6(x^5)y ³
(XY2 power) 2 power
(xy2nd power) 2nd power = x ² y^4
Find the derivative of y = (3x-5) to the power of 1 / 7,
Y = (3x-5) to the power of 1 / 7 = (3x-5) to the negative power of 7,
Let y = the negative seventh power of u, u = 3x-5,
Then y'x = y'x
=(the negative seventh power of U) 'multiplied by (3x-5)'
=-7U to the negative eighth power times 3
=-The negative octave of 21 (3x-5)
=21 / 8th power of negative (3x-5)
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