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6X5 power - 15x quartic power + 3x3 power - 3x square + X + 1 divided by 3x square, the remainder formula is x + 1 to find the quotient
Quotient = [[6X5 power - 15x quartic power + 3x3 power - 3x square + X + 1] - (x + 1)] divided by 3x square = 2x ^ 3-5X ^ 2 + 3x-1
It is known that the fourth power of polynomial - 15x + the square of 3x + X + 2 divided by the square of 3x, and the remainder is x + 2. Find the quotient?
（-15x^4+3x ²+ x+2-x-2)÷3x ²
=(-15x^4+3x ²) ÷3x ²
=-5x ²+ one
1. It is known that the division formula is 2x Square-1, the quotient formula is the 3rd power of X + 3x square-2x + 1, and the remainder formula is 2x-3. Find the divided formula?
Divided = divided × Quotient + remainder
=(2x ²- 1)(x ³+ 3x ²- 2x+1)+(2x-3)
=2x^+6x^4-5x ³- x ²+ 4x-4
It is known that the fourth power of (3x + 1) is equal to the fourth power of AX + the third power of ax, plus the second power of ax, plus the third power of a, and x plus the fourth power of A Answer: 500 points
(3x + 1) ^ 4 = 81x ^ 4 + 108x ^ 3 + 54x ^ 2 + 12x + 1 (using binomial expansion)
By comparison, other problems will be easier to solve
The main reason is that you are not very clear
It is known that the second power of x minus 3x is equal to - 1. Find the second power of (1) x + 1 / X (2) x + the second power of 1 / X (3) the fourth power of X + the fourth power of 1 / X
From known x ²+ 1 = 3x, i.e. (x) ²+ 1）/x=x+1/x=3 x ²+ 1/x ²= (x+1/x) ²- 2*x*(1/x)=3 ²- 2 = 7 x to the fourth power + 1 / X to the fourth power = (x) ²+ 1/x ²)²- 2=7 ²- 2=47
The square of x plus 3x minus 1 equals 0. What is the power of x plus one fourth of X?
Given x ^ 2 + 3x-1 = 0, find the value of x ^ 4 + 1 / x ^ 4
Divided by X on both sides of the known, we get
x+3-1/x=0
x-1/x=-3
If both sides of the above formula are square at the same time, we get
x^2+1/x^2-2=9
x^2+1/x^2=11
The two sides of the above formula are square at the same time, so we get
x^4+1/x^4+2=121
therefore
x^4+1/x^4=121-2=119
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